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Lerok [7]
3 years ago
10

Not sure if I solved this right. anyone know?

Mathematics
2 answers:
Anestetic [448]3 years ago
7 0
2tan^2x - secx = 1
Plug in the values for secx and tanx.


First choice: secx = -1
means tan^2 x = 0
2(0) - (-1) = 1

Second choice: secx = 3 = hyp/adj
means  tanx = √8
(Pythagorean theorem)
2(8) - 3 ≠ 1

Third choice: tanx = 3 = opp/adj
hyp = √(10)
means secx = √(10)
2(9) - √(10) ≠ 1

fourth choice:
tanx = -1 = opp/adj
means secx = √(2)
2(1) - √(2)  ≠ 1

fifth choice: secx = 3/2
means cosx = 2/3 ; tanx = √(5)/2
2(5/4) - 3/2 = 1

Looks like the 1st and 5th choice work.
nadya68 [22]3 years ago
6 0
Im so sorry the picture isnt loading for me -,-
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Find the area 2 m 4 m 10 m
mina [271]

Answer:

30.285 m²

Step-by-step explanation:

C = 2πr

2 · π · 2

≈ 12.57

12.57 ÷ 2 = 6.285

10 - 2 = 8

8 · 4 ÷ 2

32 ÷ 2

16

2 · 4 = 8

6.285 + 8 + 16

30.285

6 0
3 years ago
How many nonzero terms of the Maclaurin series for ln(1 x) do you need to use to estimate ln(1.4) to within 0.001?
Vilka [71]

Answer:

The estimate of In(1.4) is the first five non-zero terms.

Step-by-step explanation:

From the given information:

We are to find the estimate of In(1 . 4) within 0.001 by applying the function of the Maclaurin series for f(x) = In (1 + x)

So, by the application of Maclurin Series which can be expressed as:

f(x) = f(0) + \dfrac{xf'(0)}{1!}+ \dfrac{x^2 f"(0)}{2!}+ \dfrac{x^3f'(0)}{3!}+...  \ \ \  \ \ --- (1)

Let examine f(x) = In(1+x), then find its derivatives;

f(x) = In(1+x)          

f'(x) = \dfrac{1}{1+x}

f'(0)   = \dfrac{1}{1+0}=1

f ' ' (x)    = \dfrac{1}{(1+x)^2}

f ' ' (x)   = \dfrac{1}{(1+0)^2}=-1

f '  ' '(x)   = \dfrac{2}{(1+x)^3}

f '  ' '(x)    = \dfrac{2}{(1+0)^3} = 2

f ' '  ' '(x)    = \dfrac{6}{(1+x)^4}

f ' '  ' '(x)   = \dfrac{6}{(1+0)^4}=-6

f ' ' ' ' ' (x)    = \dfrac{24}{(1+x)^5} = 24

f ' ' ' ' ' (x)    = \dfrac{24}{(1+0)^5} = 24

Now, the next process is to substitute the above values back into equation (1)

f(x) = f(0) + \dfrac{xf'(0)}{1!}+ \dfrac{x^2f' \  '(0)}{2!}+\dfrac{x^3f \ '\ '\ '(0)}{3!}+\dfrac{x^4f '\ '\ ' \ ' \(0)}{4!}+\dfrac{x^5f' \ ' \ ' \ ' \ '0)}{5!}+ ...

In(1+x) = o + \dfrac{x(1)}{1!}+ \dfrac{x^2(-1)}{2!}+ \dfrac{x^3(2)}{3!}+ \dfrac{x^4(-6)}{4!}+ \dfrac{x^5(24)}{5!}+ ...

In (1+x) = x - \dfrac{x^2}{2}+\dfrac{x^3}{3}-\dfrac{x^4}{4}+\dfrac{x^5}{5}- \dfrac{x^6}{6}+...

To estimate the value of In(1.4), let's replace x with 0.4

In (1+x) = x - \dfrac{x^2}{2}+\dfrac{x^3}{3}-\dfrac{x^4}{4}+\dfrac{x^5}{5}- \dfrac{x^6}{6}+...

In (1+0.4) = 0.4 - \dfrac{0.4^2}{2}+\dfrac{0.4^3}{3}-\dfrac{0.4^4}{4}+\dfrac{0.4^5}{5}- \dfrac{0.4^6}{6}+...

Therefore, from the above calculations, we will realize that the value of \dfrac{0.4^5}{5}= 0.002048 as well as \dfrac{0.4^6}{6}= 0.00068267 which are less than 0.001

Hence, the estimate of In(1.4) to the term is \dfrac{0.4^5}{5} is said to be enough to justify our claim.

∴

The estimate of In(1.4) is the first five non-zero terms.

8 0
3 years ago
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Dmitriy789 [7]

Answer:

Variability (also called spread or dispersion) refers to how spread out a set of data is. Variability gives you a way to describe how much data sets vary and allows you to use statistics to compare your data to other sets of data. The four main ways to describe variability in a data set are: Range. Interquartile range. Variability is the degree to which a data series deviates from its mean  If you're going to spend money anyway, then why not get paid for it? <em>Hope This Answer Help Your Question Friend!</em>

3 0
3 years ago
Read 2 more answers
Type the correct answer in the box. Spell all words correctly.
Crank

The comlete question with the diagram is in the picture attached.

Answer:

Point   \boxed{\text{   E    }}   is the vertex of the angle marked in the figure.

Explanation:

When two lines intersect each other they will form an <em>angle</em> and the intersection point will be the <em>vertex of the angle</em>.

In the figure attached, the line that joins the points A and B and the line that joins the points C and D intersect at the point E, forming the corresponding angle (shadowed in the figure).

Such intersection point, which marks the angle, is the vertex of the angle.

3 0
3 years ago
In the following triangle,what is the length of the hypotenuse?
kati45 [8]

Step-by-step explanation:

using trigonometric ratios,

sin theta= opposite ÷ hypoteneus (h)

sin 45°= 3 root 2 ÷ h

1/root 2= 3 root 2 ÷h

h= 3× root 2 × root 2

= 3×2

= 6 unit

4 0
3 years ago
Read 2 more answers
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