<span>Given
Situation:
=> There are 408 total of ticket sold for a school play
=> 3 times of the tickets are sold to students compare to the adults
=> So the ratio of the given situation is 1 : 3
=> Now, 1 + 3 = 4
Since, we need 4 parts, let’s divide 408 by 4
=> 408 / 4 = 102 – the number of tickets for adults
=> 102 x 3 = 306 – the number of tickets for students
=> 102 : 306</span>
Answer:
Jerry paid $500.50.
Step-by-step explanation:
30 / 100 = 0.3
0.3 x 715 = 214.5
715 - 214.5 = 500.5
round to the nearest hundredth
We want to find the total number of integers that are larger than 40 and smaller than 99 that also are multiples of 3.
The answer is 18.
We can solve this just by counting.
The first multiple of 3 larger than 40 is:
3*14 = 42
Now we know that 99 is also a multiple of 3 and that the multiples of 3 are separated by a distance of 3 units, then the total number of multiples of 3 between 42 and 99 is given by:
(99 - 42)/3 = 19
But we need to remove 1, because we used 99 and we have the restriction that our numbers must be "smaller" than 99.
Then we have a total of 18 multiples of 3 between 40 and 99.
If you want to learn more, you can read:
brainly.com/question/19239363
C:
6*2 = 2.5c
c = 4.8
b:
Cannot be solved until the measure of one other angle in the X is added.
<h3>I'll teach you how to factor 20x^2-45</h3>
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20x^2-45
Factor out the common term 5:
5(4x^2-9)
Factor 4x^2-9:
(2x+3)(2x-3)
5(2x+3)(2x-3)
Your Answer Is 5(2x+3)(2x-3)
plz mark me as brainliest :)
