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3 years ago

What's the difference between 1261⁄4 and 78 2⁄3?

1 answer:

5 0

<span>So we want to know the difference between a= 126 1/4 and b= 78 2/3. Lets turn them into a fraction: a = 124*4 + 1/4 = 496/4 + 1/4 = 495/4. b= 78*3 + 2/3 = 234/3 + 2/3 = 236/3. Now we find the common denominator of a and b: and that is 12. so lets multiply a by 3/3 and b by 4/4: (495/4)*(3/3)=1485/12. (236/3)*(4/4)=944/12. Now the difference is: 1485/12 - 944/12=541/12 and that is: 45 1/12 </span>

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What is the proper seperation of factors for this equation ∛24n² × ∛36n²

Gwar [14]

Answer:

${ \tt{ \sqrt[3]{24 {n}^{2} } \times \sqrt[3]{36 {n}^{2} } }} \\ = { \tt{( {n}^{ \frac{2}{3} })( \sqrt[3]{864}) }}$

8 0

3 years ago

Please help me with this?

emmasim [6.3K]

Answer:

Step-by-step explanation:

4 0

3 years ago

10. 2x + 7y = 1<br> 2x - 4y = 12<br> Solve for y

adoni [48]

Answer:

The solution for y = -1.

Step-by-step explanation:

Given:

$2x\ +\ 7y\ =\ 1$ ....(1)

$2x\ -\ 4y\ =\ 12$ ....(2)

So, to solve for y, first we solve for x in equation (2):

$2x-4y=12$

⇒ $2x=12+4y$

Dividing both sides by 2,

⇒ $x=6+2y$

Now, substituting the value of x in equation (1):

$2x+7y=1$

⇒ $2(6+2y)+7y=1$

⇒ $12+4y+7y=1$

⇒ $12+11y=1$

⇒ $11y=1-12$

⇒ $11y=-11$

Dividing both sides by 11,

⇒ $y=-1$

Therefore, the solution for y = -1.

7 0

3 years ago

A recipe calls for 2 tablespoons of sugar for every 7 tablespoons of flour. If you plan on tripling the recipe what is the ratio

Karo-lina-s [1.5K]

you basically have to times it by 3 so

2:7

4:14

6:21

the answer would be 6 tablespoons of sugar to 21 tablespoons of flour

3 0

3 years ago

Read 2 more answers

[10] In the following given system, determine a matrix A and vector b so that the system can be represented as a matrix equation

irina1246 [14]

Answer:

$y=-\frac{158}{579}$

Step-by-step explanation:

To find the matrix A, took all the numeric coefficient of the variables, the first column is for x, the second column for y, the third column for z and the last column for w:

$A=\left[\begin{array}{cccc}1&1&2&2\\-7&-3&5&-8\\4&1&1&1\\3&7&-1&1\end{array}\right]$

And the vector B is formed with the solution of each equation of the system: $b=\left[\begin{array}{c}3\\-3\\6\\1\end{array}\right]$

To apply the Cramer's rule, take the matrix A and replace the column assigned to the variable that you need to solve with the vector b, in this case, that would be the second column. This new matrix is going to be called $A_{2}$ .

$A_{2}=\left[\begin{array}{cccc}1&3&2&2\\-7&-3&5&-8\\4&6&1&1\\3&1&-1&1\end{array}\right]$

The value of y using Cramer's rule is:

$y=\frac{det(A_{2}) }{det(A)}$

Find the value of the determinant of each matrix, and divide:

$y==\frac{\left|\begin{array}{cccc}1&3&2&2\\-7&-3&5&-8\\4&6&1&1\\3&1&-1&1\end{array}\right|}{\left|\begin{array}{cccc}1&1&2&2\\-7&-3&5&-8\\4&1&1&1\\3&7&-1&1\end{array}\right|} =\frac{158}{-579}$

$y=-\frac{158}{579}$

7 0

3 years ago