3.) 3 faces. 4 edges. 3 V
4.) 5 faces. 5 edges. 3 V
5.) 2 faces. 1 edge. 1 V
6.) 3 faces. 0 edges. 1 V
7.) 1 face. 0 edges. 2 V's
I'm iffy on the V's.
Answer:
The value of the side PS is 26 approx.
Step-by-step explanation:
In this question we have two right triangles. Triangle PQR and Triangle PQS.
Where S is some point on the line segment QR.
Given:
PR = 20
SR = 11
QS = 5
We know that QR = QS + SR
QR = 11 + 5
QR = 16
Now triangle PQR has one unknown side PQ which in its base.
Finding PQ:
Using Pythagoras theorem for the right angled triangle PQR.
PR² = PQ² + QR²
PQ = √(PR² - QR²)
PQ = √(20²+16²)
PQ = √656
PQ = 4√41
Now for right angled triangle PQS, PS is unknown which is actually the hypotenuse of the right angled triangle.
Finding PS:
Using Pythagoras theorem, we have:
PS² = PQ² + QS²
PS² = 656 + 25
PS² = 681
PS = 26.09
PS = 26
Answer:
B. 10
C. All real numbers.
Step-by-step explanation:
6 (2x-4) = 8(x + 2)
Distribute the numbers outside of the factors:
12x - 24 = 8x + 16
Subtract both sides by '8x'
12x - 8x - 24 = 8x - 8x + 16
4x - 24 = 16
Add '24' to both sides:
4x = 40
Divide both sides by 4:
x = 10. Therefore, <u>B. 10</u> is the correct answer.
3(4p - 2) = -6(1 - 2p)
Distribute the numbers similarly to the example before:
12p - 6 = -6 + 12p
Subtract '12p' from both sides:
12p - 12p -6 = -6 + 12p - 12p
0 -6 = -6
Add '6' to both sides:
0 - 6 + 6 = -6 + 6
0 = 0
Therefore, the solution consists of <u>all real numbers.</u>
Answer:
-4,-3,0,8,12 its backwards my bad
Step-by-step explanation:
because it is
