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Aleks04 [339]
2 years ago
13

In how many ways can five indistinguishable rooks be placed on an 8-by-8 chess- board so that no rook can attack another and nei

ther the first row nor the first column is empty?
Mathematics
1 answer:
german2 years ago
5 0

The are 40320 ways in which the 5 indistinguishable rooks be can be placed on an 8-by-8 chess- board so that no rook can attack another and neither the first row nor the first column is empty

<h3 /><h3>What involves the rook polynomial? </h3>

The rook polynomial as a generalization of the rooks problem

Indeed, its result is that 8 non-attacking rooks can be arranged on an 8 × 8 chessboard in r8.

Hence, 8! = 40320 ways.

Therefore, there are 40320 ways in which the 5 indistinguishable rooks be can be placed on an 8-by-8 chess- board so that no rook can attack another and neither the first row nor the first column is empty.

Read more about rook polynomial

brainly.com/question/2833285

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Step-by-step explanation:

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3 years ago
What is an equation of the line that passes through the point (3,6)(3,6) and is parallel to the line 4x-3y=214x−3y=21?
polet [3.4K]

<em><u>Question:</u></em>

What is an equation of the line that passes through the point (3,6) and is parallel to the line 4x-3y=21

<em><u>Answer:</u></em>

<em><u>The equation of the line that passes through the point (3,6) and is parallel to the line 4x-3y=21 is:</u></em>

y = \frac{4}{3}x + 2

<em><u>Solution:</u></em>

Given that line passes through the point (3,6) and is parallel to the line 4x-3y=21

<em><u>The equation of line in slope intercept form is given as:</u></em>

y = mx + c ------- eqn 1

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<em><u>Given equation is:</u></em>

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y = \frac{4}{3}x + 2

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