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Aleks04 [339]
2 years ago
13

In how many ways can five indistinguishable rooks be placed on an 8-by-8 chess- board so that no rook can attack another and nei

ther the first row nor the first column is empty?
Mathematics
1 answer:
german2 years ago
5 0

The are 40320 ways in which the 5 indistinguishable rooks be can be placed on an 8-by-8 chess- board so that no rook can attack another and neither the first row nor the first column is empty

<h3 /><h3>What involves the rook polynomial? </h3>

The rook polynomial as a generalization of the rooks problem

Indeed, its result is that 8 non-attacking rooks can be arranged on an 8 × 8 chessboard in r8.

Hence, 8! = 40320 ways.

Therefore, there are 40320 ways in which the 5 indistinguishable rooks be can be placed on an 8-by-8 chess- board so that no rook can attack another and neither the first row nor the first column is empty.

Read more about rook polynomial

brainly.com/question/2833285

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