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Aleks04 [339]
1 year ago
13

In how many ways can five indistinguishable rooks be placed on an 8-by-8 chess- board so that no rook can attack another and nei

ther the first row nor the first column is empty?
Mathematics
1 answer:
german1 year ago
5 0

The are 40320 ways in which the 5 indistinguishable rooks be can be placed on an 8-by-8 chess- board so that no rook can attack another and neither the first row nor the first column is empty

<h3 /><h3>What involves the rook polynomial? </h3>

The rook polynomial as a generalization of the rooks problem

Indeed, its result is that 8 non-attacking rooks can be arranged on an 8 × 8 chessboard in r8.

Hence, 8! = 40320 ways.

Therefore, there are 40320 ways in which the 5 indistinguishable rooks be can be placed on an 8-by-8 chess- board so that no rook can attack another and neither the first row nor the first column is empty.

Read more about rook polynomial

brainly.com/question/2833285

#SPJ4

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How many cubes with side lengths of \dfrac12 \text{ cm} 2 1 ​ cmstart fraction, 1, divided by, 2, end fraction, start text, space, c, m, end text does it take to fill the prism? ​

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81 cubes are needed to fill the prism

Step-by-step explanation:

Volume of prism = 3 cubic units

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Therefore the volume of the cube is,

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To find the number of cubes needed to fill the prism, we need to divide the volume of cube by volume of the prism.

Number of cubes to fill the prism= Volume of prism / Volume of cube

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