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Law Incorporation [45]
3 years ago
5

Neil has 3 partially full cans of white paint. They contain 1/3 of a gallon and 1/5 and 1/2 of a gallon of paint. About how much

paint does Neil have left?
Mathematics
1 answer:
allsm [11]3 years ago
3 0

Answer:

1¹/₃₀

Step-by-step explanation:

The 3 gallons were partially full

They contain 1/3 of a gallon and 1/5 and 1/2 of a gallon of paint.

the first is 1/3 of the gallon

the second is 1/5 of galloon

the third is 1/2 of gallon adding them together

1/3 +1/5 +1/2 = (10+6+15)/30 = 31/30 = 1¹/₃₀

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Please help, I need help.<br><br>I don't understand.
Lana71 [14]

Find slope of both

#1

  • (11,2)
  • (22,4)

\\ \tt\hookrightarrow m=\dfrac{4-2}{22-11}=\dfrac{2}{11}=1.8

#2

  • (0,0)
  • (5,1)

\\ \tt\hookrightarrow m=\dfrac{1-0}{5-0}=\dfrac{1}{5}=0.2

Option C is correct

7 0
2 years ago
Solve 73 make sure to also define the limits in the parts a and b
Aleks04 [339]

73.

f(x)=\frac{3x^4+3x^3-36x^2}{x^4-25x^2+144}

a)

\lim_{x\to\infty}f(x)=\lim_{x\to\infty}(\frac{3+\frac{3}{x}-\frac{36}{x^2}}{1-\frac{25}{x^2}+\frac{144}{x^4}})=3\lim_{x\to-\infty}f(x)=\lim_{x\to-\infty}(\frac{3+\frac{3}{x}-\frac{36}{x^2}}{1-\frac{25}{x^2}+\frac{144}{x^4}})=3\cdot\frac{1}{2}=3

b)

Since we can't divide by zero, we need to find when:

x^4-2x^2+144=0

But before, we can factor the numerator and the denominator:

\begin{gathered} \frac{3x^2(x^2+x-12)}{x^4-25x^2+144}=\frac{3x^2((x+4)(x-3))}{(x-3)(x-3)(x+4)(x+4)} \\ so: \\ \frac{3x^2}{(x+3)(x-4)} \end{gathered}

Now, we can conclude that the vertical asymptotes are located at:

\begin{gathered} (x+3)(x-4)=0 \\ so: \\ x=-3 \\ x=4 \end{gathered}

so, for x = -3:

\lim_{x\to-3^-}f(x)=\lim_{x\to-3^-}-\frac{162}{x^4-25x^2+144}=-162(-\infty)=\infty\lim_{x\to-3^+}f(x)=\lim_{x\to-3^+}-\frac{162}{x^4-25x^2+144}=-162(\infty)=-\infty

For x = 4:

\lim_{x\to4^-}f(x)=\lim_{n\to4^-}\frac{384}{x^4-25x^2+144}=384(-\infty)=-\infty\lim_{x\to4^-}f(x)=\lim_{n\to4^-}\frac{384}{x^4-25x^2+144}=384(-\infty)=-\infty

4 0
1 year ago
Write the equation of a line that is perpendicular to the line that passes through (4,−3)and (−7,8).
masha68 [24]

Line perpendicular to a given line is = 1/m

To find m, use m =y2-y1/x2-x1 formula

m = (8-(-3))/(-7-4)

m = 11/-11,

m = -1

Use y= mx+c to find equation of line

Plug in a pair of values,

-3= -1(4)+ c

c= 1

Thus, equation is:

y = -x+1

Equation of line perpendicular to this line is:

y= x+1

Hope it helps :)

Pls mark it as Brainliest :)

3 0
3 years ago
What is the value of 5^3¡^9
OLEGan [10]

Answer:

125i

Step-by-step explanation:

We want to find

5^3i^9

This can be rewritten as;

5^3i^8\times i

5^3(i^2)^4\times i

Recall that; i^2=-1

5^3(-1)^4\times i

We evaluate now to obtain;

125(1)\times i=125i

6 0
3 years ago
What is a^2+15^2=17^2<br><br> I can't figure out what A is... HELP PLSSSSSSSSSSSSSSSSSSSSS<br> :3
likoan [24]

Answer:

Step-by-step explanation:

3 0
3 years ago
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