the answer is 81x thank youuuuu lol
Given that,
Sample size= 83
Mean number= 39.04
Standard deviation= 11.51
We know the critical t-value for 95% confidence interval which is equal to 1.989.
We also know the formula for confidence interval,
CI=( mean number - critical t-value*standard deviation/(sample size)^(1/2), mean number + critical t-value*standard deviation/(sample size)^(1/2))
So, we have
CI= (39.04 - 1.989*11.51/83^(1/2), 39.04 + 1.989*11.51/83^(1/2)
CI= (39.04 - 2.513,39.04 + 2.513)
CI= (36.527,41.553)
Therefore, 95% confidence interval for these data is (36.527,41.553), and this result interpret that the true value for this survey sample lie in the interval (36.527,41.553).
Width = w
Length = 2w + 5/2
Perimeter = 2(Length + Width)
Perimeter = 2( w + 2w + 5/2)
Perimeter = 2(3w + 5/2)
Perimeter = 6w + 5
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Answer: The perimeter is 6w + 5 (Answer D)
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Since the length is 10 in. You must multiply it by

and then multiply by

. The reason for this is because if you divide ten by 5 it will be 2, then if you divide 2 by 2 it will be 1.