Please, share just ONE problem at a time. Thanks.
<span>Solve 2x^2-12x+20=0:
Simplify this by dividing each term by 2: x^2 - 6x + 10 = 0
Identify a, b and c: a=1, b=-6 and c=10. Then b^2=36.
Write out the solutions using the quadratic formula:
6 plus or minus sqrt(36-40)
x = ---------------------------------------
2
sqrt(36-40) = sqrt(-4) = plus or minus i2
Then:
6 plus or minus i2
x = --------------------------- (answer)
2</span>
Are u able to take a picture of the whole question?
This question is not correctly written.
Complete Question
Select all equations that can represent the question: "How many groups of 4/5 are in 1?" A ?⋅1=4/5? Times 1 is equal to 4 fifths B 1⋅4/5=?1 times 4 fifths is equal to ? C 4/5÷1=?4 fifths divided by 1 is equal to ? D ?⋅4/5=1? Times 4 fifths is equal to 1 E 1÷4/5=?1 divided by 4 fifths is equal to ?
Answer:
D ?⋅4/5=1 = ? Times 4 fifths is equal to
E 1÷4/5=? = 1 divided by 4 fifths is equal to
Step-by-step explanation:
How many groups of 4/5 are in 1?
The operation used to solve this is that Division operation.
Hence, we solve it by saying:
1 ÷ 4/5 = ?
= 1× 5/4 = ?
5/4 = ?
Cross Multiply
5 = 4 × ?
? = 5/4
The equations that can represent the question: is
Option D ?⋅4/5=1 = ? Times 4 fifths is equal to
Option E 1÷4/5=? = 1 divided by 4 fifths is equal to
Answer:
Ste-by-step explanation:
That doesn’t answer it stupid
Answer:
Step-by-step explanation:
Given
The linear equation is 
The other linear equation parallel to the given line can be represented by
Here, c can take any value . for example c=1, line becomes
