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3 years ago

HELP

Mathematics

2 answers:

alexira [117]3 years ago

8 0

True, because the triangle is symmetrical

Hope this helps :)

vodomira [7]3 years ago

6 0

Answer:

True

Step-by-step explanation:

Given: QRS is an isosceles triangle that is QS=SR and M is the mid point of QR.

To prove: ΔSQM≅ΔSRM

Proof: It is given that QRS is an isosceles triangle that is QS=SR and M is the mid point of QR, thus from ΔSQM and ΔSRM, we have

QS=SR (Given)

QM=MR (Mid point)

SM=MS (Reflexive)

Thus, by SSS rule of congruence,

ΔSQM≅ΔSRM

Hence the given statement is true, that is if M is teh point of RQ, then ΔSQM≅ΔSRM.

Hence proved.

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30= 2w + 2h<br><br> W= 3/4 h

Alexeev081 [22]

Answer:

h=60/7

w=45/7

Step-by-step explanation:

just try it.

7 0

3 years ago

Read 2 more answers

Tanya has a garden with a trench around it. The garden is a rectangle with width 2 1/2 m and length 2 m. The trench and garden t

vichka [17]

Answer:

The area of a trench is 5.5 m² .

Step-by-step explanation:

Formula

Area of a rectangle = Length × Breadth

As given

Tanya has a garden with a trench around it.

$The\ garden\ is\ a\ rectangle\ with\ width\ 2\frac{1}{2}\ m\ and\ length\ 2\ m.$

i.e

$The\ garden\ is\ a\ rectangle\ with\ width\ \frac{5}{2}\ m\ and\ length\ 2\ m.$

Put in the above formula

$Area\ of\ garden = \frac{5\times 2}{2}$

= 5 m²

As given

$The\ trench\ and\ garden\ together\ make\ a\ rectangle\ with\ width\ 3 \frac{1}{2}\ m\ and\ length\ 3 m.$

i.e

$The\ trench\ and\ garden\ together\ make\ a\ rectangle\ with\ width\ \frac{7}{2}\ m\ and\ length\ 3 m.$

$Area\ of\ garden\ with\ trench = \frac{7\times 3}{2}$

$Area\ of\ garden\ with\ trench = \frac{21}{2}$

= 10.5 m²

Area of the trench = Area of garden with trench - Area of garden

Put the value in the above

Area of the trench = 10.5 m² - 5 m²

= 5.5 m ²

Therefore the area of a trench is 5.5 m² .

5 0

3 years ago

Read 2 more answers

PLEASE HELP

ozzi

Hope this helps, I searched it up for you

6 0

2 years ago

Can someone help me with this in a scientific notation

Leviafan [203]

Answer:

3.762 x 10^-7

Step-by-step explanation:

Alright this has the same exact concept as other scientific notation problems.

First, multiply your first numbers: 4.18 x 9 = 37.62

Next, we add our powers together -4 +-4 = -8 (can also be read as -4 - 4 = -8)

We now have 37.62 x 10^-8

Wait! This isn't in scientific notation.

Taking a closer look at this we see 37.62 x 10^-8 can be adjusted by moving the decimal over to the left. Scientific notation must be in simplest form with only one number on the left of the decimal. This gives up 3.762.

Now we need to adjust our notation. Since we moved the decimal over one we are adding one more power to our problem.

Our current power of -8 is now adding a power due to moving the decimal place over one unit to the left. This is equivalent to saying -8 + 1 which equals -7. Now that we fixed our powers, we can put our equation back together for our final answer

3.762 x 10^-7

6 0

3 years ago

20% of US High School teens vape. A local High School has implemented campaigns to reduce vaping among students and believes tha

zaharov [31]

Answer:

10.93% probability of observing 51 or fewer vapers in a random sample of 300

Step-by-step explanation:

I am going to use the normal approximation to the binomial to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

$E(X) = np$

The standard deviation of the binomial distribution is:

$\sqrt{V(X)} = \sqrt{np(1-p)}$

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that $\mu = E(X)$ , $\sigma = \sqrt{V(X)}$ .