✿————✦————✿————✦————✿
The answer is: <u>2(k2−4k)(2c+5)</u>
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Step:
* Consider 2ck2+5k2−8ck−20k. Do the grouping 2ck2+5k2−8ck−20k=(2ck2+5k2) +(−8ck−20k), and factor out k2 in the first and −4k in the second group.
* Factor out the common term 2c+5 by using the distributive property.
* Rewrite the complete factored expression.
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Assume that you only include whole numbers (1,2,3,4,5,6,7,8,9) and not 3.5 and such
so if 1 is odd and less than 5 then it is
1 or 3, since 5 isn't included
then the other number, to be less than 5 when added,
must be
1+x<5
3+x<5
solve each
1+x<5
subtract 1
x<4
set of answers are 1,2,3
3+x<5
subtract 3
x<2
set of answer is 1
so the possible numbers are
1,2,3
that is 3 numbesr out of 9 so
probability=(total desired outcomes)/(total possible outcomes) so
disred outcomes=3
total possible=9
3/9=1/3
the probabiltiy is 1/3
Answer: 350,340,330,320,310,300,290,280,270,260,250,240.
Step-by-step explanation:
To solve this exercise you must keep on mind the following information:
1. By definition skip counting is about counting by a number which is not the number 1.
2. Skip counting by ten from 350 to 240 means that you need to subtract 10 to a number to find the other one.
3. Therefore, you must subtract 10 to 350 and then you need to do this over and over again until you get 240.
A=1 and 2
B=2 and 4
C=1,2,7 and 14
D=1,2,4,and 8
To answer this question you must find the percentage of the children that read before bed and compare it to the adults bag read before bed’s percentage.
To do this, start by dividing the number of children that read before bed by the total number of children surveyed.
This leaves you with:
6/13= 0.4615
To find the actual percentage, multiply this result by 100.
0.4615 x 100 = 46.15
This percentage rounded is 46%
So, now you can compare the percentages. The percentage of children that read before bed is 46% and the percentage of adults that read before bed is 54%. So, the group with the greatest percentage was the adults.
I hope this helps!