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Airida [17]
3 years ago
7

The isosceles trapezium below has perimeter 28 m. Find x and y.

Mathematics
1 answer:
cluponka [151]3 years ago
6 0

Answer:

Step-by-step explanation:

Fg

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Can someone please help
Natasha_Volkova [10]

Answer:

-6 degrees F

Step-by-step explanation:

We start with -8F as the temperature. It fell 10 degrees to 2F, then fell 8 degrees to -6F.

8 0
3 years ago
Read 2 more answers
\large -6x+6y=6<br> \large 6x+3y=12
Kaylis [27]

Answer:

the solution of the system is:

x = 1 and y = 2.

Step-by-step explanation:

I suppose that we want to solve the equation:

-6*x + 6*y = 6

6*x + 3*y = 12

To solve this, we first need to isolate one of the variables in one of the equations.

Let's isolate y in the first equation:

6*y = 6 + 6*x

y = (6 + 6*x)/6

y = 6/6 + (6*x)/6

y = 1 + x

Now we can replace this in the other equation:

6*x + 3*(1 + x) = 12

6*x + 3 + 3*x = 12

9*x + 3 = 12

9*x = 12 - 3 = 9

x = 9/9 = 1

Now that we know that x = 1, we can replace this in the equation "y = 1 + x" to find the value of y.

y = 1 + (1)  = 2

Then the solution of the system is:

x = 1 and y = 2.

6 0
3 years ago
At a dog park, there are 10 black dogs, 5 brown dogs, 2 white dogs, and 12 multi-color dogs.
ratelena [41]

Answer:

Black dogs

Step-by-step explanation:

The ratio of brown dogs to black dogs is 5:10, which simplifies to 1:2.

7 0
3 years ago
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For the following problem, assume that all given angles are in simplest form, so that if A is in QIV you may assume that 270° &l
d1i1m1o1n [39]

Answer:

Step-by-step explanation:

Given that angle A is in IV quadrant

So A/2 would be in II quadrant.

sin A = -1/3

cos A = \sqrt{1-sin^2 A} =\frac{2\sqrt{2} }{3}

(cos A is positive since in IV quadrant)

Using this we can find cos A/2

cosA = 2cos^2 \frac{A}{2} -1\\Or cos \frac{A}{2} =-\sqrt{\frac{1+cosA}{2} } =-\sqrt{\frac{3+2\sqrt{2} }{6} }

3 0
3 years ago
Help me i nedd help...........
VMariaS [17]

Answer:

The answer is 10 12/85    Hope you pass!

4 0
3 years ago
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