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serious [3.7K]
3 years ago
11

Four houses in a row are each to be painted with one of the colors red, blue, green, and yellow. In how many different ways can

the houses be painted so that no two adjacent houses are of the same color? There are possible ways to paint the houses.
Mathematics
1 answer:
Natali [406]3 years ago
3 0

Answer:

Possible ways to paint the house is 108

Step-by-step explanation:

Total number of houses to be painted=4

Total number of colours to b used(red,blue,green and yellow)=4

Number of ways to paint the first house=4

Number of ways to paint the second house=3

Number of ways to paint the third house=3

Number of ways to paint the fourth house=3

Total number of ways to paint the 4 houses=4×3^3=108 ways.

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Thepotemich [5.8K]

Answer:

slope = - \frac{4}{3}

Step-by-step explanation:

Calculate the slope m using the slope formula

m = \frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }

with (x₁, y₁ ) = (- 2, 3 ) and (x₂, y₂ ) = (4, - 5 )

m = \frac{-5-3}{4-(-2)} = \frac{-8}{4+2} = \frac{-8}{6} = - \frac{4}{3}

7 0
3 years ago
The ratio of boys to girls in a local choir is 7:10. If there are 35 boys in the choir, how many girls are there?
erica [24]

Answer:

50 girls

Step-by-step explanation:

Given data

We have the ratio as

7:10

The total part = 7+10= 17

let the number of boys and girls be x

applying the part to all method

7/17= 35/x

cross multiply

7x= 35*17

7x=595

x=595/7

x= 85

Hence the number of girls is

=85-35

=50 girls

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3 years ago
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What is the ratio of 1.6 million to 2.3 million
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Find vertical and horizontal asymtope for (x^2+2x-48)/x+8
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