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serious [3.7K]
3 years ago
11

Four houses in a row are each to be painted with one of the colors red, blue, green, and yellow. In how many different ways can

the houses be painted so that no two adjacent houses are of the same color? There are possible ways to paint the houses.
Mathematics
1 answer:
Natali [406]3 years ago
3 0

Answer:

Possible ways to paint the house is 108

Step-by-step explanation:

Total number of houses to be painted=4

Total number of colours to b used(red,blue,green and yellow)=4

Number of ways to paint the first house=4

Number of ways to paint the second house=3

Number of ways to paint the third house=3

Number of ways to paint the fourth house=3

Total number of ways to paint the 4 houses=4×3^3=108 ways.

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Answer:

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Step-by-step explanation:

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2 years ago
Help please help help please please please
AnnZ [28]

Answer:

C. \frac{5}{4}

D. \frac{6}{7}

Step-by-step explanation:

C. 2 -  \frac{12}{16}

= 2 -  \frac{3}{4}

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D. \frac{20}{22}  \times  \frac{33}{35}

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3 years ago
Worth 12 Points, i spent 24
rewona [7]

Answer:

  \displaystyle m^{\frac{35}{12}}n^{-\frac{28}{15}}=\frac{m^{\frac{35}{12}}}{n^{\frac{28}{15}}}

Step-by-step explanation:

The relevant rule of exponents is ...

  (a^b·c^d)^e = a^(be)·c^(de)

Then ...

  (m^(5/4)·n^(-4/5))^(7/3) = m^(5/4·7/3)·n^(-4/5·7/3)

  = m^(35/12)·n^(-28/15)

__

Since you want positive rational exponents, you can write this as ...

  = m^(35/12)/n^(28/15)

6 0
3 years ago
Which shows the expression below in simplified form?
statuscvo [17]

Answer:

B. 9x10^4

Step-by-step explanation:

\frac{4.5 \times  {10}^{8} }{5 \times  {10}^{3} }  \\  = 0.9 \times  {10}^{8 - 3}  \\  = 0.9 \times  {10}^{5}  \\  = 9 \times  {10}^{4}

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It is 1:45 25min later what time is it
marusya05 [52]

Answer:

The answer is 2:10

Step-by-step explanation:

60 mins in an hour. 1:45+25 is 1:70, turn that into ours and you get 2:10.

3 0
3 years ago
Read 2 more answers
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