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Debora [2.8K]
3 years ago
12

Graph system of inequalities Y>|2/3x-3 Y>|-4/3x+3

Mathematics
2 answers:
quester [9]3 years ago
7 0

The Graphs are in attachment !

1st graph is for equation :

  • y  >   \dfrac{2}{ 3}x  - 3

2nd graph is for equation :

  • y  > -  \dfrac{4}{3} x + 3

postnew [5]3 years ago
5 0

Given system of inequalities:-

y =  \frac{2}{3}x - 3

and

y =  \frac{ - 4}{3}x + 3

So, the graph for the given system of inequalities is attached along with this answer.

Please refer the attachment for the graph.

✍️ <em>By </em><em>Benjemin</em> ☺️

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That first one is the answer

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Answer:Taco Bell

Step-by-step explanation:

It’s always right g

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All vectors are in Rn. Check the true statements below:
Oduvanchick [21]

Answer:

A), B) and D) are true

Step-by-step explanation:

A) We can prove it as follows:

Proy_{cv}y=\frac{(y\cdot cv)}{||cv||^2}cv=\frac{c(y\cdot v)}{c^2||v||^2}cv=\frac{(y\cdot v)}{||v||^2}v=Proy_{v}y

B) When you compute the product Ax, the i-th component is the matrix of the i-th column of A with x, denote this by Ai x. Then, we have that ||Ax||=\sqrt{(A_1 x)^2+\cdots (A_n x)^2}. Now, the colums of A are orthonormal so we have that (Ai x)^2=x_i^2. Then ||Ax||=\sqrt{(x_1)^2+\cdots (x_n)^2}=||x||.

C) Consider S=\{(0,2),(2,0)\}\subseteq \mathbb{R}^2. This set is orthogonal because (0,2)\cdot(2,0)=0(2)+2(0)=0, but S is not orthonormal because the norm of (0,2) is 2≠1.

D) Let A be an orthogonal matrix in \mathbb{R}^n. Then the columns of A form an orthonormal set. We have that A^{-1}=A^t. To see this, note than the component b_{ij} of the product A^t A is the dot product of the i-th row of A^t and the jth row of A. But the i-th row of A^t is equal to the i-th column of A. If i≠j, this product is equal to 0 (orthogonality) and if i=j this product is equal to 1 (the columns are unit vectors), then A^t A=I    

E) Consider S={e_1,0}. S is orthogonal but is not linearly independent, because 0∈S.

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5 0
3 years ago
PLEASEEEE
belka [17]

Answer:

The answer to your questions is: 25 new teachers

Step-by-step explanation:

Data

# of students = 2000

ratio = 3:80 teachers to students

New teachers = ?

Process

I suggest to use rule of three to solve this problem

                     3 teachers ----------------  80 students

                      x                ----------------  2000 students

                  x = (2000 x 3) / 80 = 75 teachers

               Number of initial teachers = 75

The ratio change to 1:20

                     1 teacher -------------------  20 students

                     x             -------------------   2000 students

                     x = (2000 x 1) / 20

                    x = 100 teachers

Number of new teachers = 100 - 75 = 25

3 0
4 years ago
estamos construyendo una carretera que enlace los puntos a = 12 ,21 y b =(17,23) otro punto se encuentra en c =(3,9) es posible
Nadusha1986 [10]

Answer:

is not possible

Step-by-step explanation:

<u><em>The question in English is</em></u>

we are building a road that links the points a = (12 ,21) and b =(17,23) another point is in c =(3,9) it is possible that a single road allows to join these three points?

we know that

The formula to calculate the slope between two points is equal to

m=\frac{y2-y1}{x2-x1}

step 1

Find the slope ab

we have

a = (12 ,21) and b =(17,23)

substitute

m=\frac{23-21}{17-12}

m=\frac{2}{5}

step 2

Find the slope ac

we have

a = (12 ,21) and c =(3,9)

substitute

m=\frac{9-21}{3-12}

m=\frac{-12}{-9}

simplify

m=\frac{4}{3}

step 3

Compare slopes ab and ac

The slopes are different

That means ----> is not possible that a single road allows to join these three points

7 0
3 years ago
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