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3 years ago

Rounding decimals 1.079 rounded to nearest hundredth

Mathematics

2 answers:

Lilit [14]3 years ago

5 0

1.08
If you have 1.079 you round the 9 to the 7 cause it’s in the hundredth place

melisa1 [442]3 years ago

3 0

I think is 1.080 or 2.000 I don’t know???

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Solve for w, where w is a real number. √w+9=5

irga5000 [103]

If w is real then we need ignore negative sign and consider it as a mod value. So the answer will be 2

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3 years ago

7➗1/5 As a fraction plz

marishachu [46]

$\bf 7\div \cfrac{1}{5}\implies \cfrac{7}{1}\div \cfrac{1}{5}\implies \cfrac{7}{1}\cdot \cfrac{5}{1}\implies \cfrac{35}{1}$

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3 years ago

Read 2 more answers

Hello,

Damm [24]

Answer:

-1

Step-by-step explanation:

The axes on your graph are not labeled, so we have to assume they follow the usual convention. That is, the vertical axis is the y-axis, and the horizontal axis is the x-axis.

The x-coordinate tells how far to the left or right of the y-axis the point is. Here, point L is 1 grid square to the left of the vertical line that is the y-axis. If you follow the vertical line through L down to where it crosses the x-axis, you will see an unlabeled open circle there. (We don't know the purpose of that circle, but we call it to your attention so you know you're looking in the right place.)

Looking 4 more grid squares to the left of that point, you see the marking "-5". This tells you each grid square corresponds to one unit. Then the first one to the left of the y-axis (where the open circle is) has a value of -1. That is the value of the x-coordinate of point L.

The x-coordinate of point L is -1.

4 0

3 years ago

Find the area lying outside r=6cos(theta) and inside r=3+3cos(theta)

Sloan [31]

The area bounded by the 2 parabolas is A(θ) = 1/2∫(r₂²- r₁²).dθ between limits θ = a,b...

the limits are solution to 3cosθ = 1+cosθ the points of intersection of curves. 
2cosθ = 1 => θ = ±π/3 

A(θ) = 1/2∫(r₂²- r₁²).dθ = 1/2∫(3cosθ)² - (1+cosθ)².dθ 
= 1/2∫(3cosθ)².dθ - 1/2∫(1+cosθ)².dθ 
= 9/8[2θ + sin(2θ)] - 1/8[6θ + 8sinθ +sin(2θ)] .. 
.............where I have used ∫(cosθ)².dθ=1/4[2θ + sin(2θ)] 
= 3θ/2 +sin(2θ) - sin(θ) 

Area = A(π/3) - A(-π/3) 
= 3π/6 + sin(2π/3) -sin(π/3) - (-3π/6) - sin(-2π/3) + sin(-π/3) 
= π.

7 0

3 years ago

Who could help me please and thank you

kondor19780726 [428]

Answer:

"The expression represents a cubic polynomial with 3 terms. The constant term is -10, the leading degree is 3, and the leading coefficient is (-1/6)"

Step-by-step explanation:

We have the expression:

$-\frac{x^3}{6} - 10 + x$

First, what does that expression represents?

As al the powers of x are positive numbers, we can see that this is a polynomial, and the largest power is 3, so this is a polynomial of degree 3, also called a cubic polynomial.

How many terms are there?

The terms are the things separated by + or - symbols, is easy to see that there are 3 terms.

What is the constant term?

The constant term is the term where the variable, x, does not appear, here the constant term is: -10

What is the leading coefficient?

The leading coefficient is the coefficient that multiplies the term with the largest power of x, in this case, we can rewrite:

$-\frac{x^3}{6} -10 + x = (\frac{-1}{6})*x^3 - 10 + x$

the leading coefficient is:

(-1/6)

There is a part of the statement that I can't read, i suppose that there says:

"leading degree"

this is just the largest power of x that appears in the polynomial, in this case, is 3.

Then the complete statement is:

"The expression represents a cubic polynomial with 3 terms. The constant term is -10, the leading degree is 3, and the leading coefficient is (-1/6)"

5 0

3 years ago