Answer:
x^3-10x^2+x+120
Step-by-step explanation:
Assuming you mean roots -3, 5, 8
These happen when we have (x+3)(x-5)(x-8)=0
Expand this
(x^2-2x-15)(x-8)=0
=x^3-2x^2-15x-8x^2+16x+120
=x^3-10x^2+x+120
X = 3(y - 2/3) ...distribute thru the parenthesis
x = 3y - 6/3...reduce
x = 3y - 2
so ur answer is : x = 3(y - 2/3)
You can find the segment congruent to AC by finding another segment with the same length. So first, you need to find the length of AC.
C - A = AC
0 - (-6) = AC Cancel out the double negative
0 + 6 = AC
6 = AC
Now, find another segment that also has a length of 6.
D - B = BD
2 - (-2) = BD Cancel out the double negative
2 + 2 = BD
4 = BD
4 ≠ 6
E - B = BE
4 - (-2) = BE Cancel out the double negative
4 + 2 = BE
6 = BE
6 = 6
So, the segment congruent to AC is B. BE .
Y=33x + 104 -(45+66).......
