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3 years ago

Find the equation of the line. HELPPPPP

Mathematics

2 answers:

Sergio039 [100]3 years ago

8 0

(4,-7) I’m sorry if you get it wrong hope it helpss

Reptile [31]3 years ago

5 0

Answer:

y = (4/6)x + 4

Step-by-step explanation:

The format of the equation of line required is slope-intercept form:

y = mx + c

m is the slope, and c is the y-intercept.

First, lets find the slope.

Randomly find 2 points on the line. Label them as (x1, y1) and (x2, y2)

Let's say I pick the points (-6, 0) and (0, 4).

slope m = (y2 - y1) / (x2 - x1)

slope = (4-0 ) / (0 - - 6)

= 4 / 6

the y-intercept is the point where the line cuts through the y-axis, which is 4 in this case.

Therefore, the equation of line will be:

y = (4/6)x + 4

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In basketball, hang time is the time that both of your feet are off the ground during a jump. The equation for hang time is t =

const2013 [10]

Considering the hang time equation, it is found that Player 1 jumped 0.68 feet higher than Player 2.

<h3>What is the hang time equation?</h3>

The hang-time of the ball for a player of jump h is given by:

$t = 2\left(\frac{2h}{32}\right)^{\frac{1}{2}}$

The expression can be simplified as:

$t = 2\sqrt{\frac{h}{16}}$

For a player that has a hang time of 0.9s, the jump is found as follows:

$0.9 = 2\sqrt{\frac{h}{16}}$

$\sqrt{\frac{h}{16}} = \frac{0.9}{2}$

$(\sqrt{\frac{h}{16}})^2 = \left(\frac{0.9}{2}\right)^2$

$h = 16\left(\frac{0.9}{2}\right)^2$

h = 3.24 feet.

For a player that has a hang time of 0.8s, the jump is found as follows:

$0.8 = 2\sqrt{\frac{h}{16}}$

$\sqrt{\frac{h}{16}} = \frac{0.8}{2}$

$(\sqrt{\frac{h}{16}})^2 = \left(\frac{0.8}{2}\right)^2$

$h = 16\left(\frac{0.8}{2}\right)^2$

h = 2.56 feet.

The difference is given by:

3.24 - 2.56 = 0.68 feet.

More can be learned about equations at brainly.com/question/25537936

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2 years ago

Problems for you to try.

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Step-by-step explanation:

8⁴.... I hope it's correct

HAVE A GOOD DAY!

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3 years ago