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d1i1m1o1n [39]
4 years ago
6

Help please !!!!!!!!!!!!!!!!!!!!!

Mathematics
1 answer:
pshichka [43]4 years ago
7 0

Answer:

The last one

Step-by-step explanation:

volume is v= \pi r^{2} h . this means volume is mathematical number pi, times the (radius squared), times the height. the radius is marked at the yellow line, and the height on the side. this means you would have v = \pi(x+2)^{2}(3x+8)

first, lets work out (x+2)^{2}. we can rewrite this as (x+2)(x+2). we are going to use a system called FOIL. this stands for First Outside Inside Last. This means we are going to take the first number from both and multiply them together, then the outside, inside, and last. so, for first, we will multiply x and x and then we have x^{2}, for outside we multiply x and 2 and we get 2x, for inside we multiply 2 and x and we get 2x, and for last we multiply 2 and 2 and we get 4. then we add all these together. x^{2} + 2x + 2x + 4. then simplify like terms to get

x^{2} + 4x + 4. now, we can't forget about our times \pi and (3x+8)

this means we have to multiply x^{2} + 4x + 4 by those two.

it would look like this: (x^{2} + 4x + 4)(3x+8)\pi

so now we are going to multiply the other two sets of parentheses

we multiply each number from the first set to each number in the second set.

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-x+5y=5 in function notation
Aliun [14]

Answer:

y = f(x) = \frac{1}{5}x + 1

Step-by-step explanation:

The function notation of a linear function is given by y = f(x) = ax + b.

Now, the given equation is - x + 5y = 5

So, we have to arrange it for the function notation.

Now, - x + 5y = 5

⇒ 5y = x + 5

⇒ y = \frac{1}{5}(x + 5)

⇒ y = \frac{1}{5}x + 1

Therefore, the function notation of the given equation will be

y = f(x) = \frac{1}{5}x + 1 (Answer)

7 0
3 years ago
16. Sandra is choosing an Internet service provider.
Oduvanchick [21]

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Step-by-step explanation:

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Since Communication Plus costs $2.50 for every hour of Internet used, the equation to represent the cost of using the internet with them will be:

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8 0
3 years ago
For what values of a the following expressions are true: |a−5|=5−a
julia-pushkina [17]

Answer:

Whenever  a\leq 5.

Step-by-step explanation:

We can play around with some numbers and develop some rules for this equation.

Note that the number 5 and -5 are used here, so let's try using 5 as a.

|5-5| = 5-5\\|0| = 0\\0 = 0

So 5 works. Let's try a random number like 3.

|3-5| = 5-3\\|-2| = 2\\2 = 2

Okay, with this info we know that we might be able to develop one rule that a. Just to test, let's try 0, -3, and -5.

|0-5| = 5-0\\|-5| = 5\\5 = 5

Zero works.

|-3 - 5| = 5-(-3)\\|-8| = 8\\8 = 8

-3 works.

|-5 -5| = 5-(-5)\\|-10| = 10\\10 = 10

-5 works. Now, this might stop here making the equation -5 \geq  a \leq  5, so let's test a number outside of -5 - say -20.

|-20 - 5| = 5-(-20)\\|-25| = 25\\25 = 25

Yes! This works, so a works for this equation as long as a \leq 5.

Hope this helped!

8 0
3 years ago
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