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pychu [463]
4 years ago
13

Solve the equation b^2+36=0 (not 6i)

Mathematics
2 answers:
Anastaziya [24]4 years ago
6 0

I hope this helps you

b^2= - 36

b^2= - 1.6^2

b^2= i^2.(+,-6)^2

b=6i

b= - 6i

or b isn't real number there is no solution....

denpristay [2]4 years ago
3 0

Answer:  ±6i

<u>Step-by-step explanation:</u>

b^2+36=0\\\\b^2\qquad =-36\\\\\sqrt{b^2}\quad =\sqrt{-36}\\\\|b|\qquad =\sqrt{-1\cdot 6 \cdot 6}\\\\|b|\qquad =6i\\\\\large\boxed{b \qquad=\pm 6i}\\

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3 years ago
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