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3 years ago

14

Please answer asap, thanks!

1 answer:

Bad White [126]3 years ago

8 0

(So sorry I answered late, btw.. I got this from the web)

Answer:

Step-by-step explanation:

Given that In the coordinate plane line p had slope 8 and y intercept (0,5).

Hence equation of line p is

y = 8x+5 (slope intercept form)

When we dilate p by a factor of 3, we have

we find that slope would remain the same but the y intercept would become 3 times.

Hence new line would be

y = 8x+15

Slope = 8 and y intercept = 15

This line will be parallel to original line.

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A angle addition postulate

Fantom [35]

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3 years ago

N-8+n=1-4n solve for n

MrRissso [65]

Answer:

n=-N/5+9/5

Step-by-step explanation:

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4 years ago

Who do you spell this number 314,207

jok3333 [9.3K]

Three hundred fourteen thousand ,two hundred seven

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3 years ago

Read 2 more answers

n200080 [17]

Answer:

See below

Step-by-step explanation:

<u>Zeroes</u>

$f(x)=2(x-1)(x+3)$

$0=2(x-1)(x+3)$

$0=(x-1)(x+3)$

$x=1$ and $x=-3$

$(1,0)$ and $(-3,0)$

<u>Axis of Symmetry</u>

$f(x)=2(x-1)(x+3)$

$y=2(x-1)(x+3)$

$y=2(x^2+2x-3)$

$y+2(4)=2(x^2+2x-3+4)$

$y+8=2(x^2+2x+1)$

$y+8=2(x+1)^2$

$y=2(x+1)^2-8$

$y=a(x-h)^2+k$

$x=h$

$x=-1$

<u>Vertex</u>

$y=a(x-h)^2+k$

$y=2(x+1)^2-8$

$(h,k)\rightarrow(-1,-8)$

<u>Y-intercept</u>

$f(x)=2(x-1)(x+3)$

$f(0)=2(0-1)(0+3)$

$f(0)=2(-1)(3)$

$f(0)=-6$

$y=-6$

$(0,-6)$

Please review the attached graph for a visual of these key features.

5 0

3 years ago

Count the possible combinations of 2 letters chosen from L, M, N, O. The possible combinations of 2 letters are __.

Ronch [10]

Answer:

The possible combinations of two letters is 12

Step-by-step explanation:

Here, we want to count the possible combinations of two letters

Now, for the first letter any point in time, we have 4 letters to pick from,

For the second letter we have 3 letters to pick from

So therefore, we have the possible combinations as;

4 * 3 = 12

7 0

3 years ago