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nika2105 [10]
3 years ago
8

Fiona wrote the linear equation y = x – 5. When Henry wrote his equation, they discovered that his equation had all the same sol

utions as Fiona’s. Which equation could be Henry’s?
Mathematics
2 answers:
Veronika [31]3 years ago
8 0
It could be:
y=-X+5
no ?
agasfer [191]3 years ago
6 0
Fiona equation is y= x-5
So Henry's equation would be x= y+5 by adding 5 for both sides of the equation

To check, let's say x=2

Fiona equation y= 2-5= -3

Henry equation when x=2, 2= y+5 so, y= 2-5= -3
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the perimeter of square is 36 inches which statement is true when the square is dilated by a scale factor of 2/3
OlgaM077 [116]

Answer:

Do you want to know the new perimeter?  = 24 in

Step-by-step explanation:

side of 36" perimeter = 9"

9 x 2/3 = 6 in

perimeter of 6" square = 24 in

7 0
2 years ago
Select all the points that are on the line through (0 5) and (2 8) A.(5 11) B.(5 10) C.(6 14) D.(30 50) E.(40 60)
mihalych1998 [28]

Answer:

Options C. and D. are correct.

Step-by-step explanation:

Let (x_1,y_1)=(0,5),\,(x_2,y_2)=(2,8)

Equation of a line is given by y-y_1=(\frac{y_2-y_1}{x_2-x_1})(x-x_1)

y-5=(\frac{8-5}{2-0})(x-0)\\\\y-5=\frac{3}{2}x\\\\2y-10=3x\\3x-2y+10=0

Put  (x,y)=(5,11)

3(5)-2(11)+10=15-22+10=3\neq 0

Put  (x,y)=(5,10)

3(5)-2(10)+10=15-20+10=5\neq 0

Put (x,y)=(6,14)

3(6)-2(14)+10=18-28+10=0

Put (x,y)=(30,50)

3(30)-2(50)+10=90-100+10=0

Put (x,y)=(40,60)

3(40)-2(60)+10=0\\120-120+10=10\neq 0

So, points (6,14),\,(30,50) satisfy the equation 3x-2y+10=0

Therefore,

points (6,14),\,(30,50) lie on the line through (0,5) and (2,8)

Options C. and D. are correct.

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3 years ago
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antiseptic1488 [7]

Answer:

Step-by-step explanation:

5 0
3 years ago
The difference between 31 and a number is 7
astra-53 [7]

Answer:

thirty-eight

Step-by-step explanation:

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5 0
3 years ago
Read 2 more answers
Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used. Match each quadratic equation with its so
Anon25 [30]

The quadratic equations and their solutions are;

9 ± √33 /4 = 2x² - 9x + 6.

4 ± √6 /2 = 2x² - 8x + 5.

9 ± √89 /4 = 2x² - 9x - 1.

4 ± √22 /2 = 2x² - 8x - 3.

Explanation:

  • Any quadratic equation of the form, ax² + bx + c = 0 can be solved using the formula x = -b ± √b² - 4ac / 2a. Here a, b, and c are the coefficients of the x², x, and the numeric term respectively.
  • We have to solve all of the five equations to be able to match the equations with their solutions.
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  • 2x² - 8x - 3, here a = 2, b = -8, c = -3.                                                    x = -b ± √b² - 4ac / 2a = -(-8) ± √(-8)² - 4(2)(-3) / 2(2) = 8 ± √64 + 24/4.     88 can also be written as 4 × 22 and √4 = 2. So                                                                             x = 8 ± 2√22 / 2×2 = 4± √22/2.
  • 2x² - 9x - 1, here a = 2, b = -9, c = -1.                                                     x = -b ± √b² - 4ac / 2a = -(-9) ± √(-9)² - 4(2)(-1) / 2(2) = 9 ± √81 + 8/4.                                          x = 9 ± √89 / 4.
  • 2x² - 9x + 6, here a = 2, b = -9, c = 6.                                                    x = -b ± √b² - 4ac / 2a = -(-9) ± √(-9)² - 4(2)(6) / 2(2) = 9 ± √81 - 48/4.                                                                             x = 9 ± √33 / 4 .

8 0
3 years ago
Read 2 more answers
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