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Sonja [21]
3 years ago
11

Pleasee help me on my bellwork!!!! i will mark you BRAINLIEST!!!

Mathematics
1 answer:
brilliants [131]3 years ago
5 0
17/2, 8 and 1/2 or 8.5 are all the correct answers.
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See the picture below
mart [117]

Answer:

a) 301.59 cubic centimeters

b) 235.87 square centimeters

Step-by-step explanation:

a)

Volume of ice cream cone is volume of hemisphere PLUS volume of cone.

Volume of Hemisphere = \frac{\frac{4}{3}\pi r^3}{2}

radius is given as 4, so,

Volume of Hemisphere = \frac{\frac{4}{3}\pi r^3}{2}\\=\frac{\frac{4}{3}\pi (4)^3}{2}\\=134.04

Now, Volume of Cone = \frac{1}{3}\pi r^2 h

Where radius is 4 and height is 10, so,

Volume of Cone = \frac{1}{3}\pi r^2 h\\=\frac{1}{3}\pi (4)^2 (10)\\=167.55

Volume of Ice Cream Cone = 134.04 + 167.55 = 301.59 cubic centimeters

b)

Surface area of ice cream cone is surface area of hemisphere PLUS surface area of cone.

Surface Area of Hemisphere = 2\pi r^2\\=2\pi (4)^2\\=100.53

Surface Area of Cone = \pi r^2+\pi rl

We dont need to use the first part, \pi r^2  since it is "inside". We  need to find l, slant height, by using pythagorean theorem on a triangle we can make (bottom right).

4^2 + 10^ 2 = l^2

16 + 100 = l^2

116 = l^2

l = 10.77

Now to find the surface area of cone = \pi rl\\=\pi (4)(10.77)\\=135.34

Surface area of ice cream cone = 100.53 + 135.34 = 235.87 square centimeters

5 0
2 years ago
(X-2/3)^2+y^2 =36 <br> What is its center? <br> What is its radius
Hatshy [7]

Answer:

0(2/3; 0)

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
-4x + 2(5x - 6) = 6(x - 2)
Ugo [173]

Answer:

Sorry but this equation gives me 6x-12=6x-12

Step-by-step explanation:

Hope u don't mind me asking but have u tried it out yet and what did you get???

Is that a negative b4 4x??

8 0
2 years ago
I need help. it’s due tonight.thank you
masha68 [24]

Answer:28

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Estimate the limit<br><br> A <br> B <br> C<br> D
Lera25 [3.4K]

Answer:

C. \lim_{x\rightarrow f(x)=2

Step-by-step explanation:

Given problem is \lim_{x\rightarrow \frac{\pi}{4}}\frac{tan(x)-1}{x-\frac{\pi}{4}}.

Now we need to evaluate the given limit.

If we plug \x=\frac{\pi}{4}, into given problem then we will get 0/0 form which is an indeterminate form so we can apply L Hospitals rule

take derivative of numerator and denominator

\lim_{x\rightarrow \frac{\pi}{4}}\frac{tan(x)-1}{x-\frac{\pi}{4}}

=\lim_{x\rightarrow \frac{\pi}{4}}\frac{sec^2(x)-0}{1-0}

=\frac{sec^2(\frac{\pi}{4})-0}{1-0}

=\frac{(\sqrt{2})^2}{1}

=\frac{2}{1}

=2

Hence choice C is correct.

5 0
3 years ago
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