Which equation, when graphed, has x-intercepts at (8, 0) and (−2, 0) and a y-intercept at (0, −48)?

Mathematics

2 answers:

MakcuM [25]3 years ago

7 0

the answer is C.f(x) = 3(x − 8)(x + 2)

Leto [7]3 years ago

3 0

Answer:

f(x) = 3(x − 8)(x + 2)

Step-by-step explanation:

The roots are at x = 8 and x = -2. This means factored form would include

y = (x-8)(x+2), with some number a as the leading coefficient.

Multiplying through, we have

y = x²+2x-8x-16

y = x²-6x-16

To have a y-intercept at -48, this means we multiply the function by 3; this gives us

y = 3(x-8)(x+2)

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