Answer:
<em>∠TUV = 56°</em>
Step-by-step explanation:
<em>∠TUV = 1/2 ∠TWV</em>
<em>∠TUV = 112° ÷ 2 = 56°</em>
It is a completely true statement that a <span>degree is larger than 30 arc minutes. The correct option among the two options that are given in the question is the first option. 30 arc minutes is almost equal to 1/2 degree. I hope that this is the answer that you were looking for and the answer has actually come to your great help.</span>
$=(a^2-10a)-(b^2+6b) +16$
$=[(a^2-2(5)a+25)-25]-[(b^2+2(3)b+9)-9]+16$
$=(a-5)^2-25-(b+3)^2+9+16$
$=(a-5)^2-(b+3)^2$
Multiply 14 to each term: 14a+70+84b
C. 42.39 times 0.1 is 4.239. 42.39-4.239= 38.151 which rounds to 38.15
