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butalik [34]
3 years ago
13

What is the transformation of A(4,6) when dilated with a scale factor of 2, using the point (2,1) as the center of dilation?

Mathematics
1 answer:
LUCKY_DIMON [66]3 years ago
4 0

Answer:

Option B

Step-by-step explanation:

Given that the point A(4,6) is dilated with a scale factor of 2

about the point O(2,1) as centre of dilation

This implies that the new point A' will lie on the lineOA with distance equal to double of OA.

Or A will be the mid point of OA' and AA' will have same slope as OA

Considering the above two conditions we find that

Option A cannot be right.

Option B:  Midpoint of OA' = (4,6) matches with given

Slope of AA'=\frac{11-6}{6-4} =\frac{5}{2}\\\\\frac{6-1}{4-2}= \frac{5}{2}\

= slope of OA

Thus option B satisfies both

So answer is B

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The figure is not drawn to scale. PQ and MN are straight lines. Find
nataly862011 [7]

Answer:

a = 138

Step-by-step explanation:

Notice that from the figure, we can see that ∠MOQ and ∠PON are vertical angles, which means that by definition, they're congruent in measure.

∠MOQ = ∠MOR + ∠ROQ = 90 + 48 = 138°

So, this means that ∠PON is also equal to 138, which means a = 138.

Thus, the answer is a = 138.

<em>~ an aesthetics lover</em>

5 0
3 years ago
How long will it take a deposit of $4500 at an annual rate 5.75% to earn $1035? Please Show Work PLZ
garik1379 [7]
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3 0
3 years ago
Which is the equation of a parabola with a directrix at y = −3 and a focus at (5, 3)?
kramer

Answer:

y = 1/12 (x − 5)²

Step-by-step explanation:

We can solve this graphically without doing calculations.

The y component of the focus is y = 3.  Since this is above the directrix, we know this is an upward facing parabola, so it must have a positive coefficient.  That narrows the possible answers to A and C.

The x component of the focus is x = 5.  Since this is above the vertex, we know the x component of the vertex is also x = 5.

So the answer is A. y = 1/12 (x−5)².

But let's say this wasn't a multiple choice question and we needed to do calculations.  The equation of a parabola is:

y = 1/(4p) (x − h)² + k

where (h, k) is the vertex and p is the distance from the vertex to the focus.

The vertex is halfway between the focus and the directrix.  So p is half the difference of the y components:

p = (3 − (-3)) / 2

p = 3

k, the y component of the vertex, is the average:

k = (3 + (-3)) / 2

k = 0

And h, the x component of the vertex, is the same as the focus:

h = 5

So:

y = 1/(4×3) (x − 5)² + 0

y = 1/12 (x − 5)²

3 0
3 years ago
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5 0
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4vir4ik [10]

If you're looking for equivalents to 3^x, choices

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7 0
3 years ago
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