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2 years ago

Which formula can be used to find the nth term in a geometric sequence where a1=3 and r=2 ?

2 answers:

8 0

1st term =a₁ = 3, r=2

1st a₁   = 3 x 2⁰
2nd a₂  = 3 x 2¹
3rd a₃ = 3 x 2²
4th a₄   = 3 x 2³
5th a₅   = 3 x 2⁴
.......................
.......................
nth : a(n) = 3 x 2⁽ⁿ-¹)
Note when that the subscript of a is the same as the exponent mines 1

shusha [124]2 years ago

7 0

A(n)=a(1)*r^(n-1)

a(n)=3*2^(n-1)

Hope I don't mess up for your sake.

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Which means the sum of w and 3.4 is greater than or equal to 10.5

zhuklara [117]

$w+3.4 \geq 10.5$

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2 years ago

The Witches coven are making a potion and Ethel, Glinda, Locasta and Circe each add a different ingredient. When the potion is f

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2 years ago

186:403 in simpleast form<br><br>

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Step-by-step explanation:

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3 years ago

James has a board that is 3/4 foot long. He wants to cut the board into pieces that are each 1/8 foot long

mina [271]

Answer=6 pieces

First lets convert 3/4 to ?/8...

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3/4 is equivalent to 6/8.

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4 0

2 years ago

Read 2 more answers

In your notebook, set up the following subtraction in a vertical format and select the correct answer. Find 2p 2 3p - 4 less - 2

Elena L [17]

The equation in the reduced form of the equation is $\rm 4p^ 2 + 6p - 8$ .

Given that,

Equation; $\rm 2p^ 2 + 3p - 4\ by\ -2p ^2 - 3p +4$

We have to reduce the equation.

According to the question,

To reduce the equation means we need to subtract one equation from the other.

To determine the reduced form of the equation following all the steps given below.

Equation; $\rm 2p^ 2 + 3p - 4\ by\ -2p ^2 - 3p +4$

Subtraction equation 1 from equation 2,

$\rm = \rm 2p^ 2 + 3p - 4\ -(-2p ^2 - 3p + 4)\\\\= 2p^ 2 + 3p - 4\ -(-2p ^2 -3p +4)\\\\ = 2p^ 2 + 3p - 4+2p^ 2 + 3p - 4 \\\\ = 4p^ 2 + 6p - 8$

Hence, The equation in the reduced form of the equation is $\rm 4p^ 2 + 6p - 8$ .

For more details refer to the link given below.

brainly.com/question/1807316

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2 years ago