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2 years ago

13

a car is traveling at a speed of 108 kilometers per hour. What is the cars speed in kilometers per minute? How many kilometers w

ill the car travel in 10 minutes? Do not round your answers.

2 answers:

Naya [18.7K]2 years ago

7 0

Answer: 10.8 km per min

Step-by-step explanation:

12345 [234]2 years ago

6 0

Answer:

6.71081 miles per 10 min or

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Please help if possible due today thank you so so much!!

LenKa [72]

It’s B, B is the answer

7 0

2 years ago

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Let f be defined by the function f(x) = 1/(x^2+9)

riadik2000 [5.3K]

(a)

$\displaystyle\int_3^\infty \frac{\mathrm dx}{x^2+9}=\lim_{b\to\infty}\int_{x=3}^{x=b}\frac{\mathrm dx}{x^2+9}$

Substitute <em>x</em> = 3 tan(<em>t</em> ) and d<em>x</em> = 3 sec²(<em>t </em>) d<em>t</em> :

$\displaystyle\lim_{b\to\infty}\int_{t=\arctan(1)}^{t=\arctan\left(\frac b3\right)}\frac{3\sec^2(t)}{(3\tan(t))^2+9}\,\mathrm dt=\frac13\lim_{b\to\infty}\int_{t=\arctan(1)}^{t=\arctan\left(\frac b3\right)}\mathrm dt$

$=\displaystyle \frac13 \lim_{b\to\infty}\left(\arctan\left(\frac b3\right)-\arctan(1)\right)=\boxed{\dfrac\pi{12}}$

(b) The series

$\displaystyle \sum_{n=3}^\infty \frac1{n^2+9}$

converges by comparison to the convergent <em>p</em>-series,

$\displaystyle\sum_{n=3}^\infty\frac1{n^2}$

(c) The series

$\displaystyle \sum_{n=1}^\infty \frac{(-1)^n (n^2+9)}{e^n}$

converges absolutely, since

$\displaystyle \sum_{n=1}^\infty \left|\frac{(-1)^n (n^2+9)}{e^n}\right|=\sum_{n=1}^\infty \frac{n^2+9}{e^n} < \sum_{n=1}^\infty \frac{n^2}{e^n} < \sum_{n=1}^\infty \frac1{e^n}=\frac1{e-1}$

That is, ∑ (-1)ⁿ (<em>n</em> ² + 9)/<em>e</em>ⁿ converges absolutely because ∑ |(-1)ⁿ (<em>n</em> ² + 9)/<em>e</em>ⁿ| = ∑ (<em>n</em> ² + 9)/<em>e</em>ⁿ in turn converges by comparison to a geometric series.

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2 years ago

what is the distance of the ramp in feet? in the picture and please help answer the question below !!!

azamat

The answer is
sin 35 =5/x

0.57=5/x
X= 8.77

4 0

3 years ago

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Limit as x approaches 0 of csc3x/cotx

jolli1 [7]

Hello Meggieh821, to find the lim as x approaches 0 we can check this by inserting a number that is close to 0 that is coming from the left and from the right.

For instance, we can find the lim by using the number -.00001 for x and solve
<span>csc(3x) / cot(x)
</span>csc(3*-.00001) / cot(-.00001) = .333333... = 1 /3

We also need to check coming from the right. We will use the number .00001 for x
csc(3x) / cot(x)
csc(3*.00001) / cot(.00001) = .333333... = 1 /3

So since we are getting 1/3 from the left and right we can say as x approaches 0 the limit is 1/3

<span> $\lim_{x\to 0} \frac{csc(3x)}{cot(x)} = \frac{1}{3}$ </span>

6 0

2 years ago

If f(x)=x-1/x g(x)=x-1 and h(x)=x+1 what is (g•h•f)(x)

eimsori [14]

Answer:

( f o f )(x) = f ( f (x))

= f (2x + 3)

= 2( ) + 3 ... setting up to insert the input

= 2(2x + 3) + 3

= 4x + 6 + 3

= 4x + 9Step-by-step

explanation:

8 0

3 years ago

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