Question

Lesson 6 Homework Practice

Answer 1

Answer:

Products: Each product can be mentally solved, we need to multiply each factor by the units digit and then add it to the product with the tenths, as follows

1. $8 \times 34 \implies (8\times 4)+ (8 \times 30)=32+240=272$

2. $5 \times 47 = (5 \times 7)+ (5 \times 40)=35+200=235$

3. $12 \times 43= (12 \times 3)+(12 \times 40)=36+480=516$

4. $8 \times 33=(8 \times 3) + (8 \times 30)=24+240=264$

5. $6 \times 4.4=60 \times 44=(60 \times 4)+(60 \times 40)=240+2400=2640 \implies 26.40$

6. $7 \times 2.9= 70 \times 29=(70 \times +9)+(70 \times 20)=630+1400=2030 \implies 20.30$

Distributive property: Remember, distributive property is about "distributing" the outside factor with each term in side the parenthesis, as follows

7. $6(n+4)=6\times n + 6\times 4=6n+24$

8. $15(2+r)=15 \times 2 + 15 \times r=30+15r$

9. $8(s+5)=8 \times s + 8 \times 5= 8s+40$

10. $3(b+8)=3b+24$

11. $5(6+b)=60+5b$

12. $9(3+v)=27+9v$

13. $7(r-7)=7r-49$

14. $12(4-v)=48-12v$

15. $11(3-s)=33-3s$

The given table shows the prices. Ticket $8.50, Popcorn $5.25, Soda $4.00, Candy $3.75 and Nachos $6.

a. Each of four bought a tickets and a bag of popcorn, the money spent is

$4(tickets)+4(popcorn)=4(8.50)+4(5.25)=34+21=\ 55$

They spend $55 in total.

b. 12 kids buy a box of candy and a soda.

$12(candy)+12(soda)=12(3.75)+12(4)=45+48=\ 93$

They spent $93 in total.

c. The difference between three orders of nachos and three bags of popcorn.

$3(nachos)-3(popcorn)=3(6)-3(5.25)=18-15.75=\ 2.25$

So, the difference between both orders is $2.25.

Answer 2

C. is the answer to this