Question

Solve the Quadratic Equation By Completing the Square b^2-15b-54=0

Answer 1

$b^{2}-15b-54=0. \newline b^{2}-15b=54. \newline b^{2}-15b+(\frac{15}{2})^{2}=54+(\frac{15}{2})^{2}. \newline (b-\frac{15}{2})^{2}=\frac{441}{4}. \newline b-\frac{15}{2}=\pm\frac{21}{2}. \newline b=\pm\frac{21}{2}+\frac{15}{2}. \newline b_1 = -3, b_2 = 18.$