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Verdich [7]
4 years ago
6

HELPPPP please !!!!!,!!?

Mathematics
2 answers:
Aleks04 [339]4 years ago
8 0

Answer:

mercury has higher density than venus

lions [1.4K]4 years ago
4 0

Mercury has the greater density than that of Venus .

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Need help on this one
malfutka [58]

Answer:

3

Step-by-step explanation:

To simplify this expression, we will simply work with the numerator, then the denominator, and then the fraction as a whole, following PEMDAS.

Numerator:  12 - 6 + 5 * (-3)^2

= 12 - 6 + 5 * (9)

= 12 - 6 + 45

= 6 + 45

= 51

Denominator:  17

So our simplified fraction is as follows:

51/17

Which can be reduced to the whole number, 3.

Cheers.

3 0
3 years ago
Examine the system of equations.
earnstyle [38]

Answer:

The correct answer is B(2)

Step-by-step explanation:

I did it and somehow got it right.

6 0
3 years ago
Read 2 more answers
Add 1m 35cm to 3m 90cm 25mm
iren2701 [21]
<span>1m +
35cm = .35m +
3m +
90cm =.90 m +
25mm = .025m +

</span>
<span><span>+ 1.0 m
+ 0.35m
+ 3.0 m
+ 0.90 m
+ 0.025m</span>

= 5.275 meters

</span>
8 0
3 years ago
Let F(x) = x^2 – 15 and <br> G(x)= 4 - x<br> Find (F/G)(–7) =
KATRIN_1 [288]

Answer:

\displaystyle \bigg( \frac{F}{G} \bigg)(-7) = \frac{34}{11}

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Algebra I</u>

  • Functions
  • Function Notation

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

F(x) = x² - 15

G(x) = 4 - x

<u>Step 2: Find</u>

  1. Substitute in functions:                                                                                     \displaystyle \bigg( \frac{F}{G} \bigg)(x) = \frac{x^2 - 15}{4 - x}

<u>Step 3: Evaluate</u>

  1. Substitute in <em>x</em> [Function (F/G)(x)]:                                                                    \displaystyle \bigg( \frac{F}{G} \bigg)(-7) = \frac{(-7)^2 - 15}{4 - (-7)}
  2. Exponents:                                                                                                         \displaystyle \bigg( \frac{F}{G} \bigg)(-7) = \frac{49 - 15}{4 - (-7)}
  3. Subtract:                                                                                                            \displaystyle \bigg( \frac{F}{G} \bigg)(-7) = \frac{34}{11}
8 0
3 years ago
Given the points R (6,-2) and T (-9,- 7), find the coordinates of point S on line RT such that the ratio of RS to ST is 3 : 2​ p
Sholpan [36]

Answer:

(-3, -5)

Step-by-step explanation:

By using the distance formula, we see that the length of RT is \sqrt{(6+9)^2+(-2+7)^2} which equals 5\sqrt{10}.

The ratio of RS to ST is 3:2, so we can write the distance of RS as (5\sqrt{10} / 5) * 3 which equals 3\sqrt{10}. The distance of ST is then 2\sqrt{10}.

Since we know the distance of RS and ST, we can find the coordinates of point S by using the distance formula again:

\sqrt{(6-x)^2+(-2-y)^2} = 3\sqrt{10} and \sqrt{(-9-x)^2+(-7-y)^2} = 2\sqrt{10}

We solve for x and y, getting (-3, -5).

3 0
3 years ago
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