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2 years ago

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(-42.27,4.4) and (2.27,3.1) what is the slope?

1 answer:

kaheart [24]2 years ago

4 0

Answer:

i need one more brainliest and i will level up can u gimme brainliest THXXXXXXXXX!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Step-by-step explanation:

<h2><u>HELP KEY FOR SLOPE RIGHT HERE!</u></h2>

Using the Slope Equation:

Pick two points on the line and determine their coordinates.

Determine the difference in y-coordinates of these two points (rise).

Determine the difference in x-coordinates for these two points (run).

Divide the difference in y-coordinates by the difference in x-coordinates (rise/run or slope).

How do you calculate rise over run?

Multiply the slope by the run to calculate the rise between subsequent points. In the example, if you wanted to know the rise given a run of 10, multiply 10 times 0.6 to calculate a rise of 6. Divide the rise by the slope to calculate the run.

What does a slope of mean?

The slope of a line is the steepness of the line. There are many ways to think about slope. Slope is the rise over the run, the change in 'y' over the change in 'x', or the gradient of a line.

How do I find slope?!

<u>The slope of a line characterizes the direction of a line. To find the slope, you divide the difference of the y-coordinates of 2 points on a line by the difference of the x-coordinates of those same 2 points .</u>

I do not know the exact answer to ur question but this was just a help key for you. :) maybe it helped? :)

PLEASE GIVE ME BRAINLIEST! have a great day.

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Who can help on this for brainliest ?

k0ka [10]

Answer:

6

Step-by-step explanation:

$1\frac{1}{2}$ ÷ $\frac{1}{4}$ =

$\frac{3}{2} *\frac{4}{1}$ =

6

Hope this helps!

Pls give brainliest

8 0

2 years ago

Read 2 more answers

miskamm [114]

Throughout this, I'm assuming that the scale is: 1 square = 1

Not 100% sure if my answers are correct.

Question 1:

The x coordinate must be 2 and the y coordinate must be -1.

Question 2:

The x coordinate would be -2 and the y coordinate would be -1.

4 0

2 years ago

I need help please I don’t know what to it is due today

Kazeer [188]

Answer:

12 blue necklaces + 12 red necklaces = 24 necklaces. He will have 1 blue bead left over and 1 red bead left over.

Step-by-step explanation:

37/3 = 12.333 or 12 r1

25/2= 12.5 or 12 r1

1+1=2

6 0

2 years ago

Read 2 more answers

In Exercises 40-43, for what value(s) of k, if any, will the systems have (a) no solution, (b) a unique solution, and (c) infini

svet-max [94.6K]

Answer:

If k = −1 then the system has no solutions.

If k = 2 then the system has infinitely many solutions.

The system cannot have unique solution.

Step-by-step explanation:

We have the following system of equations

$x - 2y +3z = 2\\x + y + z = k\\2x - y + 4z = k^2$

The augmented matrix is

$\left[\begin{array}{cccc}1&-2&3&2\\1&1&1&k\\2&-1&4&k^2\end{array}\right]$

The reduction of this matrix to row-echelon form is outlined below.

$R_2\rightarrow R_2-R_1$

$\left[\begin{array}{cccc}1&-2&3&2\\0&3&-2&k-2\\2&-1&4&k^2\end{array}\right]$

$R_3\rightarrow R_3-2R_1$

$\left[\begin{array}{cccc}1&-2&3&2\\0&3&-2&k-2\\0&3&-2&k^2-4\end{array}\right]$

$R_3\rightarrow R_3-R_2$

$\left[\begin{array}{cccc}1&-2&3&2\\0&3&-2&k-2\\0&0&0&k^2-k-2\end{array}\right]$

The last row determines, if there are solutions or not. To be consistent, we must have k such that

$k^2-k-2=0$

$\left(k+1\right)\left(k-2\right)=0\\k=-1,\:k=2$

Case k = −1:

$\left[\begin{array}{ccc|c}1&-2&3&2\\0&3&-2&-1-2\\0&0&0&(-1)^2-(-1)-2\end{array}\right] \rightarrow \left[\begin{array}{ccc|c}1&-2&3&2\\0&3&-2&-3\\0&0&0&-2\end{array}\right]$

If k = −1 then the last equation becomes 0 = −2 which is impossible.Therefore, the system has no solutions.

Case k = 2:

$\left[\begin{array}{ccc|c}1&-2&3&2\\0&3&-2&2-2\\0&0&0&(2)^2-(2)-2\end{array}\right] \rightarrow \left[\begin{array}{ccc|c}1&-2&3&2\\0&3&-2&0\\0&0&0&0\end{array}\right]$

This gives the infinite many solution.

5 0

3 years ago

Word problem plz help thanks fam 7.04

givi [52]

g/2 + 4

last option is the answer

4 0

2 years ago

Read 2 more answers