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3 years ago

A snowmobile is priced at $2,800 and is on sale for 20% off the sales tax rate is 8.25 % what is the sale price including tax

Mathematics

1 answer:

balu736 [363]3 years ago

7 0

2424.8 is the price value included with tax

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Y/-7 = 1/14<br> y = ?<br> pls answer as a reduced fraction.

mote1985 [20]

Answer:

y = -1/2

Step-by-step explanation:

−7⋅

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3 years ago

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The vertices of a trapezoid are located at (1, 2), (3, 1), (3, 5), (1, 4). The trapezoid is translated 4 units to the right. Wha

padilas [110]

Answer:

Suppose that we have a given point (x, y)

If we translate this point N units to the right, then the new coordinates of the point are:

(x + N, y)

Ok, now if we know that the vertices of the trapezoid are:

(1, 2), (3, 1), (3, 5), (1, 4)

And we move the whole figure 4 units to the right, then all the vertices are moved 4 units to the right.

Then the new vertices of the figure will be:

(1 + 4, 2) = (5, 2)

(3 + 4, 1) = (7, 1)

(3 + 4, 5) = (7, 5)

(1 + 4, 4) = (5, 4)

Then the coordinates of the image of the trapezoid (of the new vertices) are:

(5, 2), (7, 1), (7, 5), (5, 4)

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3 years ago

1.08 x 10^-3 in standard form?

Olenka [21]

AnswerTo the following subject of 1.08×10 in standard form you have to calculate the radius in yet to find the perimeter

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3 years ago

Help me with this question, please?

Virty [35]

Answer:vertices

Step-by-step explanation:

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3 years ago

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A tank contains 300 liters of fluid in which 40 grams of salt is dissolved. Brine containing 1 gram of salt per liter is then pu

bonufazy [111]

Answer:

A(t) = 300 -260e^(-t/50)

Step-by-step explanation:

The rate of change of A(t) is ...

A'(t) = 6 -6/300·A(t)

Rewriting, we have ...

A'(t) +(1/50)A(t) = 6

This has solution ...

A(t) = p + qe^-(t/50)

We need to find the values of p and q. Using the differential equation, we ahve ...

A'(t) = -q/50e^-(t/50) = 6 - (p +qe^-(t/50))/50

0 = 6 -p/50

p = 300

From the initial condition, ...

A(0) = 300 +q = 40

q = -260

So, the complete solution is ...

A(t) = 300 -260e^(-t/50)

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The salt in the tank increases in exponentially decaying fashion from 40 grams to 300 grams with a time constant of 50 minutes.

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