The correct question is
<span>Given cos theta=4/9 and csc theta < 0 find sin theta and tan theta
</span>
we know that
csc theta=1/sin theta
if csc theta < 0
then
sin theta < 0
we have that
<span>cos theta=4/9
we know that
sin</span>² theta+cos² theta=1
so
sin² theta=1-cos² theta-----> 1-(4/9)²----> 1-(16/81)----> 65/81
sin theta=-√(65/81)---->-√65/9
the answer Part a) is
sin theta=-√65/9
Part b) find tan theta
tan theta=sin theta/cos theta
tan theta=(-√65/9)/(4/9)-----> tan theta=-√65/4
the answer part b) is
tan theta=-√65/4
Idk but it can't be 10 or 9.7 bc a triangle's hypotenuse is always longer than its legs
Answer:
Step-by-step explanation:
area=πr^2
so we need to find the area then divide by 8
so
we know that diameter=2radius or diameter/2=radius so
12=diameter
12/2=radius=6
subsitute
area=π(6)^2
area=36π
divide 36π by 8
36π/8=18π/4=9π/2π=4.5π
area of one section is 4.5π square feet or if we aprox pito 3.14159 then we get
4.5(3.14159)=area=14.1372 square feet or 14.14 square feet
First let’s multiply. 8x-4=-3x+32. Start collecting like terms on different sides. 8x+3x=32+4. 11x=36. x=36/11. x=3.27.
Answer:
44
Step-by-step explanation:
x + (x+2) + (x+4) + (x+6) + (x+8) + (x+10) = 294
Combine all like terms for x and integers
6x + 30 = 294
Minus 30 on both sides
6x = 264
Divide by 6
x = 44