All categories

2 years ago

HEY U OVER THERE! WANT SOME POINTS ANSWER THIS FOR 35!!!!!!

Mathematics

2 answers:

Anuta_ua [19.1K]2 years ago

7 0

Answer:

Step-by-step explanation:

x + (x+2) + (x+4) + (x+6) + (x+8) + (x+10) = 294
Combine all like terms for x and integers
6x + 30 = 294

Minus 30 on both sides
6x = 264
Divide by 6
x = 44

Xelga [282]2 years ago

6 0

Answer:

Step-by-step explanation:

<u>Let's name the 6 consecutive terms as</u>

x, x + 2, x + 4, x + 6, x + 8 + x + 10

x + x + 2 + x + 4 + x + 6 + x + 8 + x + 10 = 294

<u>Solution:</u>

x + x + 2 + x + 4 + x + 6 + x + 8 + x + 10 = 294
=> 6x + 30 = 294
=> 6x = 294 - 30
=> 6x = 264
=> x = 264/6
=> x = 44

Hence, the smallest number among the six consecutive numbers is 44.

You might be interested in

Someone pls answer this it’s so confusing lol

GenaCL600 [577]

Answer:

Step-by-step explanation:

w = yh - 2yc³

First of all factorize y out of the expression on the right side of the equation

That's

w = y( h - 2c³)

Next divide both sides by (h - 2c³) to make y stand alone

We have

We have the final answer as

Hope this helps you

4 0

3 years ago

1.) Simplify: y = -8 + 6(x-1)

swat32

8+6=14. (X-1=1x)

14•1x

6 0

2 years ago

Which data is represented by this plot?

RSB [31]

Answer:

a)

Step-by-step explanation:

Data represented by the plot: 0, 1, 1, 1, 2, 3, 4, 4, 6, 7 & 8

B) & C) Can’t be answers cuz of 2 0’s

So it’s between A) & D)

Well D is missing one more 1 in the data plot so the answer is A

6 0

2 years ago

Triangle ABC has vertices A(0, 4), B(2, 1), and C(4, 3). Find the

dmitriy555 [2]

A(0,-4)
B(2,-1)
C(4,-3)

6 0

3 years ago

Use the substitution of x=e^{t} to transform the given Cauchy-Euler differential equation to a differential equation with consta

kherson [118]

By the chain rule,

$\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{\mathrm dy}{\mathrm dt}\dfrac{\mathrm dt}{\mathrm dx}\implies\dfrac{\mathrm dy}{\mathrm dt}=x\dfrac{\mathrm dy}{\mathrm dx}$

which follows from $x=e^t\implies t=\ln x\implies\dfrac{\mathrm dt}{\mathrm dx}=\dfrac1x$ .

$\dfrac{\mathrm dy}{\mathrm dt}$ is then a function of $x$ ; denote this function by $f(x)$ . Then by the product rule,

$\dfrac{\mathrm d^2y}{\mathrm dx^2}=\dfrac{\mathrm d}{\mathrm dx}\left[\dfrac1x\dfrac{\mathrm dy}{\mathrm dt}\right]=-\dfrac1{x^2}\dfrac{\mathrm dy}{\mathrm dt}+\dfrac1x\dfrac{\mathrm df}{\mathrm dx}$