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alexdok [17]
4 years ago
8

Write the fraction or mixed number as a percent 43/50

Mathematics
2 answers:
jok3333 [9.3K]4 years ago
5 0

Answer:

86%

Step-by-step explanation:

Check attachment

satela [25.4K]4 years ago
5 0

Answer:

86%

Step-by-step explanation:

43/50 is a proper fraction because the numerator is smaller than the denominator.

43/50 as a percentage is

43/50 x 100%

0.86 x 100%

86%

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Graph the line with slope 1/4 and y intercept -2
andrey2020 [161]

Answer:

y= 1/4x -2

Step-by-step explanation:

Y=mx+b

m is the slope

b is the y intercept

8 0
3 years ago
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Solve the equation for y.<br> 3y = -6x + 1<br> y =
polet [3.4K]
The answer is y=-2x+1/3
5 0
3 years ago
Open or closed circle?<br><br>What is the answer for the number line?<br><br>What is the solution?
Amanda [17]

To isolate m, we'll multiply both sides by 8.

We go from m/8 < 4 to m < 32

This describes any number smaller than 32. We aren't including 32 itself, so we have an <u>open circle</u> at 32 on the number line. The <u>shading is to the left</u> since everything to the left of 32 is smaller than 32.

3 0
3 years ago
The value of which of these expressions is closest to e?
pishuonlain [190]
The correct answer for the exercise shown above, is the first option (Option A), which is:

 A. <span>(1+1/18)^18

 The explanation is shown below:

 1- You have that the number e is an irrational number, therefore, its value is aproximated:

 e=2.7182

 2- You have the following expressions:

 </span>(1+1/18)^18=2.6464 
 <span>(1+1/17)^17=2.6424
 </span><span>(1+1/16)^16=2.6379
 </span><span>(1+1/15)^15=2.6328

 Therefore the value of the expression that is closest to e is the Option A.</span>
5 0
3 years ago
If α, β are the zeroes of the polynomials f(x) = x2 – p(x + 1) – c, then (α + 1)(β + 1) =
Pavlova-9 [17]

Answer:

f(x) = x2 – p(x + 1) – c, then (α + 1)(β + 1)f(x) = x2 – p(x + 1) – c, then (α + 1)(β + 1)

Step-by-step f(x) = x2 – p(x + 1) – c, then (α + 1)(β + 1)explanation:

f(x) = x2 – p(x + 1) – c, then (α + 1)(β + 1)f(x) = x2 – p(x + 1) – c, then (α + 1)(β + 1)f(x) = x2 – p(x + 1) – c, then (α + 1)(β + 1)f(x) f(x) = x2 – p(x + 1) – c, then (α + 1)(β + 1)p(x + 1) – c, then (α + 1)(β + 1)f(x) = x2 – p(xf(x) = x2 – p(x + 1) – c, then (α + 1)(β + 1) + 1) – c, then (α + 1)(β + 1)f(x) = x2 – p(xf(x) = x2 – p(x + 1) – c, then (α + 1)(β + 1) + 1) – c, then (α + 1)(β + 1)f(x) = x2 – p(x + 1) – c, then (α + 1)(β + 1)

4 0
3 years ago
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