I'm assuming you mean
, not
, like your prompt suggests.
First, let's figure out what rule we can use. A likely noticeable one is the Power Rule, which says the following:
![\dfrac{d}{dx} [u^a] = a(u)^{a-1} du](https://tex.z-dn.net/?f=%5Cdfrac%7Bd%7D%7Bdx%7D%20%5Bu%5Ea%5D%20%3D%20a%28u%29%5E%7Ba-1%7D%20du)
Applying this, we can solve for the derivative:
![f'(x) = 2(e^x + 5x) (e^x + 5)](https://tex.z-dn.net/?f=f%27%28x%29%20%3D%202%28e%5Ex%20%2B%205x%29%20%28e%5Ex%20%2B%205%29)
While you can simplify the expression to your liking, I believe that this form is not overly complex and will thus leave it as is.
Thus, our answer is:
![f'(x) = \boxed{2 (e^x + 5x)(e^x + 5)}](https://tex.z-dn.net/?f=f%27%28x%29%20%3D%20%5Cboxed%7B2%20%28e%5Ex%20%2B%205x%29%28e%5Ex%20%2B%205%29%7D)
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Answer:What is the proportionality constant in the 3y 2x equation? Since the equation can be written in the form y = kx y = k x, y varies directly with x and k. The variation constant k is 23.
Answer:
It isn't hard to find out if your working 1 hour a day for 10 days you would have 130 dollars
Step-by-step explanation:
So take the extra 3 off right? 10x10 is 100 so then 10x3=30 100+30=130