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Sveta_85 [38]
3 years ago
15

In a box of crayons, 24% of the crayons are blue. There are 48 blue crayons in the box. Select from the drop-down menu to correc

tly identify the total number of crayons in the box.
Mathematics
2 answers:
Lemur [1.5K]3 years ago
6 0
X=total number of crayons
0.24(X)=48
X=48/0.24
X=200
zmey [24]3 years ago
6 0
I took 48÷24% to get the total number of crayons in the box because if you multiply a number by a percent you get whatever is like, 7% of 100, if you divide a number (48) by a percent (24%) you GET the original number (200) that was multiplied by the percent (24%) to get the number you HAVE (48). So, the total number of crayons is 200.
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Choose the two rectangular prisms that have a volume of 36cm^3?
oee [108]

Answer:

<em>Correct choices: B, D</em>

Step-by-step explanation:

<u>The Volume of a Rectangular Prism</u>

Given a rectangular prism of dimension W, L, and H, the volume is calculated as:

V = WLH

Each small cube of the figure has a volume of 1 cube centimeter. We need to calculate the volume of each solid and determine which ones have a volume of 36 cube cm.

A: V = 5*3*4 = 60 cube cm

B: V = 3*3*4 = 36 cube cm

C: V = 3*4*2 = 24 cube cm

D: V = 6*2*3 = 36 cube cm

E: V = 2*4*2 = 16 cube cm

Correct choices: B, D

8 0
2 years ago
In a standard deck of cards there 52 cards of which 26 are black and 26 are red. Additionally, there are 4 suits, hearts, clubs,
stich3 [128]

Using probability concepts, it is found that P(S and D) = 0.1275.

-----------------------

  • A probability is the <u>number of desired outcomes divided by the number of desired outcomes</u>.
  • In a standard deck, there are 52 cards.
  • Of those, 13 are spades, and 13 are diamond.

  • The probability of selecting a spade with the first card is 13/52. Then, there is a 13/51 probability of selecting a diamond with the second. The same is valid for diamond then space, which means that the probability is multiplied by 2. Thus, the desired probability is:

P(S \cap D) = 2 \times \frac{13}{52} \times \frac{13}{51} = \frac{2\times 13 \times 13}{52 \times 51} = 0.1275

Thus, P(S and D) = 0.1275.

A similar problem is given at brainly.com/question/12873219

7 0
2 years ago
Real Answers Only!!!!
lyudmila [28]

Answer:

The correct answer is C) Reflection across the Y-axis.

Step-by-step explanation:

This is because only the x-coordinates changed. If these coordinates were reflected across both the x and y axis' the sign of both the x and y coordinates would have changed. When  you reflect a point across the x axis, the y-coordinates change their sign. When you <u><em>reflect </em></u><u>a point across the y axis</u>, the <u>x-coordinates change</u> their sign.

Hope this helps,

♥<em>A.W.E.</em><u><em>S.W.A.N.</em></u>♥

5 0
3 years ago
In the star below, all of the inscribed angles are congruent. Find the measure of each inscribed angle.
ozzi

Answer:

36 degrees for each angle.

Step-by-step explanation:

If you divide 180 by 5 (for each point in the star) you get 36 degrees.

7 0
2 years ago
An object is launched at 29.4 meters per
Lerok [7]

Answer:

The reasonable domain for the scenario is option 'a';

a) [0, 7]  

Step-by-step explanation:

For the projectile motion of the object, we are given;

The speed at which the object is launched, v = 29.4 meters per second

The height of the platform from which the object is launched, h = 34.3 meter

The equation for the height of the object as a function of time 'x' is given as follows;

f(x) = -4.9·x² + 29.4·x + 34.3

The domain for the scenario, is given by the possible values of 'x' for the function, which is found as follows;

At the height from which the object is launched, x = 0, and f(x) = 34.3

At the ground level to which the object can drop, f(x) = 0

∴ f(x) = -4.9·x² + 29.4·x + 34.3 = 0

-4.9·x² + 29.4·x + 34.3 = 0

By the quadratic formula, we have;

x = (-29.4 ± √(29.4² - 4 × (-4.9) × 34.3))/(2 × (-4.9)

∴ x = -1, or 7

Given that time is a natural number, we have the reasonable domain for the scenario as the start time when the object is launched, t = 0 to the time the object reaches the ground, t = 7

Therefore, the reasonable domain for the scenario is; 0 ≤ x ≤ 7 or [0, 7].

4 0
3 years ago
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