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dmitriy555 [2]
3 years ago
6

yuto left his house for bike ride at 10am. when riko left yuto was 5.25 miles along path. if yutos average speed was 0.25 mpm an

d rikos was 0.35mpm , over what time period in minutes,t, strting from when riko left will riko be behind yuto
Mathematics
1 answer:
Shtirlitz [24]3 years ago
8 0
-- When Riko left the house, Yuto was 5.25 miles ahead of her.

-- From the time she left the house, she gained (0.35 - 0.25) = 0.1 mile on Yuto
every minute ... closing the gap at the rate of 0.1 mile per minute.

-- If she can keep it up, she'll close the gap in (5.25 / 0.1) = 52.5 minutes.

-- Riko is behind her brother when  0 ≤ t < 52.5 minutes .


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1+2+3+4+5+6+7+8+9+1+2+3+4+5+6+7+8+9+10 times 2
Maksim231197 [3]

Answer:

200

Step-by-step explanation:

<u>Step 1:  Add</u>

1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10

1 + 2 = 3

3 + 3 = 6

6 + 4 = 10

10 + 5 = 15

15 + 6 = 21

21 + 7 = 28

28 + 8 = 36

36 + 9 = 45

45 + 1 = 46

46 + 2 = 48

48 + 3 = 51

51 + 4 = 55

55 + 5 = 60

60 + 6 = 66

66 + 7 = 73

73 + 8 = 81

81 + 9 = 90

90 + 10 = 100

<em>100</em>

<u>Step 2:  Multiply</u>

100 * 2

<em>200</em>

Answer:  200

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