Question

What is the equation, in point-slope form, of the line that has a slope of 6 and passes through the point (–1, –8)? a. y+8 = 6 (x+1 )

Answer 1

Answer:

y + 8 = 6(x + 1)

Step-by-step explanation:

The equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

here m = 6 and (a, b) = (- 1, - 8), hence

y - (- 8) = 6(x - (- 1)), that is

y + 8 = 6(x + 1)

Answer 2

ANSWER

$y + 8=6(x + 1)$

EXPLANATION

The point-slope form of an equation is given by the formula:

$y-y_1=m(x-x_1)$

Where

$(x_1,y_1)$

is a point on this line and

$m$

is the slope of the line.

From the question, the line has slope 6 and passes through (-1,-8).

This means that

$x_1=-1$

$y_1=-8$

and

$m = 6$

We substitute these values into the point-slope formula to get:

$y- - 8=6(x- - 1)$

We simplify to get:

$y + 8=6(x + 1)$