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Alexeev081 [22]

3 years ago

7

If a triangle has side lengths 27, 79, and 84 is it a right triangle

1 answer:

timofeeve [1]3 years ago

4 0

Answer:

Nope

Step-by-step explanation:

A right triangle must have a 90 degree angle.

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given y>0 and dy/dx=(3x^2+4x)/yif the point (1,√10) is on the graph relating x and y, then what is y when x=0

jonny [76]

$\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{3x^2+4x}y\iff y\,\mathrm dy=(3x^2+4x)\,\mathrm dx$
$\implies\displaystyle\int y\,\mathrm dy=\int(3x^2+4x)\,\mathrm dx$
$\implies \dfrac12y^2=x^3+2x^2+C$

When $x=1$ you have $y=\sqrt{10}$ , so

$\dfrac12(\sqrt{10})^2=1^3+2(1)^2+C\implies 5=1+2+C\implies C=2$

and so the particular solution to the ODE is

$\dfrac12y^2=x^3+2x^2+2$

Then when $x=0$ , you get

$\dfrac12y^2=0^3+2(0)^2+2=2$
$\implies y^2=4$
$\implies y=2$

where we omitted the negative root because it's given that $y>0$ .

4 0

3 years ago

Pls help I really need it ASAP

gtnhenbr [62]

Answer:

0, -1 for part A -1,-9 for part B

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

12345 what is the answer if you multiply 1x2x3x4x5 and do the same with subtraction, addition and devision, in that order. Then

Alexandra [31]

Well, we just need to perform the operations:

Multiplication: $1\cdot 2 \cdot 3 \cdot 4 \cdot 5 = 120$
Subtraction: $1-2-3-4-5 = -13$
Addition: $1+2+3+4+5 = 15$
Division: $1 \div 2 \div 3 \div 4 \div 5 = \frac{1}{120}$

So, if you add all the numbers together you get

$120-13+15+\dfrac{1}{120} = 122 + \dfrac{1}{120}$

Or, if you prefer,

$\dfrac{1681}{120}$

8 0

3 years ago

aleta's puppy gained 3/8 pounds each week for 4 weeks. altogether, how much weight did the puppy gained

Arturiano [62]

1 1/2 pounds is how much her puppy gained altogether

8 0

3 years ago

Can someone please help me with this asap ... Please and thank you

OLga [1]

Answer:

Step-by-step explanation:

From the question given in the picture,

a). Since, NR bisects a straight angle ∠MNP,

∠MNR ≅ ∠PNR

m∠MNR + m∠PNR = 180°

2(m∠MNR) = 180°

m∠MNR = 90°

Therefore, ∠MNR and ∠PNR are the right angles.

Since, QN divides ∠MNR in two parts,

Therefore, ∠QNR will be an acute angle (less than 90°).

∠MNR + ∠SNR = ∠MNS

90° + ∠SNR = ∠MNS

Therefore, m∠MNS will be more than 90°.

∠MNS will be an obtuse angle (greater than 90°).

(b). Since, NR divides ∠MNP and ∠QNS,

∠MNR ≅ ∠PNR

∠QNR ≅ ∠SNR

∠MNQ ≅ ∠PNS

(c). m∠MNR = 90°

Since, NR bisects ∠QNS,

∠QNR ≅ ∠RNS

m∠QNR = m∠RNS = 30°

m∠QNR + m∠RNS = 30° + 30°

m∠QNR + m∠RNS = 60°

m∠QNS = 60° [Since, m∠QNS = m∠QNR + m∠RNS]

m∠QNP = m∠QNS + m∠SNP

m∠QNP = m∠QNS + (m∠PNR - m∠SNR)

m∠QNP = 60° + (90° - 30°) = 120°

4 0

3 years ago