Answer:
Isosceles Right Triangle Example
Step-by-step explanation:
Find the area and perimeter of an isosceles right triangle whose hypotenuse side is 10 cm. Therefore, the length of the congruent legs is 5√2 cm. Therefore, the perimeter of an isosceles right triangle is 24.14 cm.
Hope this answer helps ^^
We have to solve two inequations:
Equation 1:
30(x-1)≥0
(x-1)≥0/30
(x-1)≥0
x≥1 (solution 1)
Equation 2:
5x²≥0
x≥0
The solution is: solution1 <span>∩ solution2
Teherefore; x≥1</span>
<u> 12x³ - 12x </u><u /> = 3/7 - 1/56x² - 3/7 = 3/7 - 3/7 - 1/56x² = -1/56x²
28x³ - 56x² + 28x
-3,450, -0.6, 3.85, 14
Smallest to greatest --->
If you know the area of the square is 256 and the area of the circle is 200.96 you subtract 200.96 from 256 and you get 55.04 is the area of the square that is not covered by the circle. so 55.04/256 because that will give you the percent of the area that is outside that circle but inside the square and you get .215 or 21.50%
