All categories

3 years ago

Find the 100th term in the arithmetic sequence -19,-14,-9,-4,1... a. 100 c. 476 b. 471 d. 481

Mathematics

1 answer:

musickatia [10]3 years ago

8 0

Answer:

c.) 476

Step-by-step explanation:

Arithmetic Sequence

-19; -14; -9; -4; 1;............aₙ

aₙ = 5n - 24

a₁₀₀ = 5(100) - 24

a₁₀₀ = 476

You might be interested in

Find the value of x

vodka [1.7K]

Answer:

x = 70

y = 110

z = 30

Step-by-step explanation:

all triangles add up to 180

30 + 80 = 110

180 - 110 = 70

x = 70

30 + 40 = 70

70 + 80 = 150

180 - 150 = 30

z = 30

40 + 30 = 70

180 - 70 = 110

y = 110

7 0

3 years ago

helppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppp

yarga [219]

Answer:

the first box and the second box

6 0

3 years ago

Determine the average rate of change of the function between the given values of the variable. g(x)=2/x ; x=4, x=a

IrinaK [193]

Average rate of change implies the quotient f(4)-f(a)/4-a which equals (1/2-a/2)/4-a=(1-a)/(8-2a) on (4,a)

3 0

3 years ago

Find the area of the triangle ABC with the coordinates of A(10, 15) B(15, 15) C(30, 9).

lions [1.4K]

Check the picture below. so, that'd be the triangle's sides hmmm so let's use Heron's Area formula for it.

$~\hfill \stackrel{\textit{\large distance between 2 points}}{d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}}~\hfill~ \\\\[-0.35em] ~\dotfill\\\\ (\stackrel{x_1}{10}~,~\stackrel{y_1}{5})\qquad (\stackrel{x_2}{15}~,~\stackrel{y_2}{15}) ~\hfill a=\sqrt{[ 15- 10]^2 + [ 15- 5]^2} \\\\\\ ~\hfill \boxed{a=\sqrt{125}} \\\\\\ (\stackrel{x_1}{15}~,~\stackrel{y_1}{15})\qquad (\stackrel{x_2}{30}~,~\stackrel{y_2}{9}) ~\hfill b=\sqrt{[ 30- 15]^2 + [ 9- 15]^2} \\\\\\ ~\hfill \boxed{b=\sqrt{261}}$

$(\stackrel{x_1}{30}~,~\stackrel{y_1}{9})\qquad (\stackrel{x_2}{10}~,~\stackrel{y_2}{5}) ~\hfill c=\sqrt{[ 10- 30]^2 + [ 5- 9]^2} \\\\\\ ~\hfill \boxed{c=\sqrt{416}} \\\\[-0.35em] ~\dotfill$

$\qquad \textit{Heron's area formula} \\\\ A=\sqrt{s(s-a)(s-b)(s-c)}\qquad \begin{cases} s=\frac{a+b+c}{2}\\[-0.5em] \hrulefill\\ a=\sqrt{125}\\ b=\sqrt{261}\\ c=\sqrt{416}\\ s\approx 23.87 \end{cases} \\\\\\ A\approx\sqrt{23.87(23.87-\sqrt{125})(23.87-\sqrt{261})(23.87-\sqrt{416})}\implies \boxed{A\approx 90}$

6 0

2 years ago

Graph y+6 = 4/5 (x+3 using the point and slope given in the equation.

egoroff_w [7]

Answer:

Slope: 4/5

Point: (-3|-6)

4 0

3 years ago