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White raven [17]
3 years ago
12

6 3/4 + 3 1/8 please whats the answer

Mathematics
2 answers:
Natalka [10]3 years ago
6 0

Answer:

9 7/8 is the answer, hope this helps!

Step-by-step explanation:

Vesnalui [34]3 years ago
3 0

Step-by-step explanation: so 9 7/8

hope this hleps you some

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What is y=-5/3x-6 in standard form
andre [41]

Answer: 5x+3y=-18

Step-by-step explanation:

7 0
3 years ago
Please Help! What is the distance between points (2, 8) and (7, 5)? Round to the nearest tenth of a unit.
zavuch27 [327]
Distance formula is like pythagoren ahtoerem
D=\sqrt{(7-2)^{2}+(5-8)^{2}}
the distance between oints (x1,y1) and (x2,y2) is
D=\sqrt{(x2-x1)^{2}+(y2-y1)^{2}}
(2,8) and (7,5)
D=\sqrt{(7-2)^{2}+(5-8)^{2}}
D=\sqrt{(5)^{2}+(-3)^{2}}
D=\sqrt{25+9}
D=\sqrt{34}
apxos
D=5.8309....

round
D=5.8 units


6 0
3 years ago
Read 2 more answers
At a specific point on a highway, vehicles arrive according to a Poisson process. Vehicles are counted in 12 second intervals, a
morpeh [17]

Answer: a) 4.6798, and b) 19.8%.

Step-by-step explanation:

Since we have given that

P(n) = \dfrac{15}{120}=0.125

As we know the poisson process, we get that

P(n)=\dfrac{(\lambda t)^n\times e^{-\lambda t}}{n!}\\\\P(n=0)=0.125=\dfrac{(\lambda \times 14)^0\times e^{-14\lambda}}{0!}\\\\0.125=e^{-14\lambda}\\\\\ln 0.125=-14\lambda\\\\-2.079=-14\lambda\\\\\lambda=\dfrac{2.079}{14}\\\\0.1485=\lambda

So, for exactly one car would be

P(n=1) is given by

=\dfrac{(0.1485\times 14)^1\times e^{-0.1485\times 14}}{1!}\\\\=0.2599

Hence, our required probability is 0.2599.

a. Approximate the number of these intervals in which exactly one car arrives

Number of these intervals in which exactly one car arrives is given by

0.2599\times 18=4.6798

We will find the traffic flow q such that

P(0)=e^{\frac{-qt}{3600}}\\\\0.125=e^{\frac{-18q}{3600}}\\\\0.125=e^{-0.005q}\\\\\ln 0.125=-0.005q\\\\-2.079=-0.005q\\\\q=\dfrac{-2.079}{-0.005}=415.88\ veh/hr

b. Estimate the percentage of time headways that will be 14 seconds or greater.

so, it becomes,

P(h\geq 14)=e^{\frac{-qt}{3600}}\\\\P(h\geq 14)=e^{\frac{-415.88\times 14}{3600}}\\\\P(h\geq 14)=0.198\\\\P(h\geq 14)=19.8\%

Hence, a) 4.6798, and b) 19.8%.

7 0
3 years ago
HELP PLEASE<br><br> Combine like terms to create an equivalent expression.
k0ka [10]
SOLUTION:

= ( 7 / 8 )m + 9 / 10 - 2m - 3 / 5

= - ( 9 / 8 )m + 3 / 10
6 0
4 years ago
How do I solve this problem
quester [9]
I think x equals 54


Hope this helps
4 0
3 years ago
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