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Colt1911 [192]
3 years ago
15

A student figures that he has a 4141​% chance of being let out of class late. If he leaves class​ late, there is a 3030​% chance

that he will miss his train. What is the probability that he gets out of class late and misses the​ train?
Mathematics
1 answer:
andreev551 [17]3 years ago
5 0

Answer:

12.3%

Step-by-step explanation:

In this case, despite being different events, they are dependent on each other, therefore the final probability would be the multiplication of both probabilities.

So let L be the probability of being late that is equal to 41% and let T be the probability that the train will leave you and is equal to 30%.

That is to say:

L = 41% = 0.41

T = 30% = 0.3

So:

P = L * T

P = 0.41 * 0.3 = 0.123

So it means that the final probability is 12.3%

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Yesterday, the snow was 2 feet deep in front of Archie’s house. Today, the snow depth dropped to 1.6 feet because the day is so
IgorLugansk [536]

Answer: The depth of the snow has changed .4 inches. This is because it has melted in the warm weather. You can find the difference, by subtracting 1.6 from 2.          

Step-by-step explanation:

2 - 1.6= .4    .4 would be your answer

Hope it helps!!!!

4 0
3 years ago
If ABCD is an A4 sheet and BCPO is the square, prove that △OCD is an isosceles triangle. And find the angles marked as 1 to 8 wi
Dmitry [639]

Answer:

The diagram for the question is missing, but I found an appropriate diagram fo the question:

Proof:

since OC = CD = 297mm Therefore, Δ OCD is an isoscless triangle

∠BCO = 45°

∠BOC = 45°

∠PCO = 45°

∠POC = 45°

∠DOP = 22.5°

∠PDO = 67.5°

∠ADO = 22.5°

∠AOD = 67.5°

Step-by-step explanation:

Given:

AB = CD = 297 mm

AD = BC = 210 mm

BCPO is a square

∴ BC = OP = CP = OB = 210mm

Solving for OC

OCB is a right anlgled triangle

using Pythagoras theorem

(Hypotenuse)² = Sum of square of the other two sides

(OC)² = (OB)² + (BC)²

(OC)² = 210² + 210²

(OC)² = 44100 + 44100

OC = √(88200

OC = 296.98 = 297

OC = 297mm

An isosceless tringle is a triangle that has two equal sides

Therefore for △OCD

CD = OC = 297mm; Hence, △OCD is an isosceless triangle.

The marked angles are not given in the diagram, but I am assuming it is all the angles other than the 90° angles

Since BC = OB = 210mm

∠BCO = ∠BOC

since sum of angles in a triangle = 180°

∠BCO + ∠BOC + 90 = 180

(∠BCO + ∠BOC) = 180 - 90

(∠BCO + ∠BOC) = 90°

since ∠BCO = ∠BOC

∴  ∠BCO = ∠BOC = 90/2 = 45

∴ ∠BCO = 45°

∠BOC = 45°

∠PCO = 45°

∠POC = 45°

For ΔOPD

Tan\ \theta = \frac{opposite}{adjacent}\\ Tan\ (\angle DOP) = \frac{87}{210} \\(\angle DOP) = Tan^-1(0.414)\\(\angle DOP) = 22.5 ^{\circ}

Note that DP = 297 - 210 = 87mm

∠PDO + ∠DOP + 90 = 180

∠PDO + 22.5 + 90 = 180

∠PDO = 180 - 90 - 22.5

∠PDO = 67.5°

∠ADO = 22.5° (alternate to ∠DOP)

∠AOD = 67.5° (Alternate to ∠PDO)

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3 years ago
How many sides does a quadrillateral have
masya89 [10]

Answer: 4

Step-by-step explanation:In geometry a quadrilateral is a four-sided polygon, having four edges and four corners. The word is derived from the Latin words quadri, a variant of four, and latus, meaning side

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2 years ago
8.4×0.5 showing work​
Katen [24]
Can u add a picture?
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2 years ago
13.3x + 8.1 = 74.6<br><br> A. 6.2<br> B. 6 <br> C. 5<br> D. 0.5
navik [9.2K]

13.3x + 8.1 = 74.6


C. 5

7 0
3 years ago
Read 2 more answers
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