Question

Max's grade on the first math exam was a 94. His grade on his seond math exam was an 89. What was the percent of change in Max's grade to the nearest whole perent.

Answer 1

We are given that

Max's grade on the first math exam was a 94

so, first exam grade =94

His grade on his seond math exam was an 89

so, second exam grade =89

change in grade=(first exam grade)-(second exam grade)

change in grade=94-89

change in grade=5

Percentage = ( change in grade)/( first exam grade) *100

so, percentage is

$=\frac{5}{94}\times 100$

so,

the percent of change in Max's grade to the nearest whole percentage was 5%..........Answer

Answer 2

Answer:

The percent of change in grade was "5% decrease"

Step-by-step explanation:

Max's grade on the first math exam was 94 and his grade on his second math exam was 89.

So, the grade is decreased by (94 - 89) = 5

For finding the percentage of change in grade, we will just divide the "grade decreased" by the "initial grade" and then multiply that by 100%.

So,  $\frac{5}{94}\times 100\% = \frac{500}{94}\%= 5.31...\% \approx 5\%$

Thus, the percent of change in Max's grade to the nearest whole percent was  5% decrease.