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g100num [7]
3 years ago
9

Max's grade on the first math exam was a 94. His grade on his seond math exam was an 89. What was the percent of change in Max's

grade to the nearest whole perent.
Mathematics
2 answers:
Tom [10]3 years ago
5 0

We are given that

Max's grade on the first math exam was a 94

so, first exam grade =94

His grade on his seond math exam was an 89

so, second exam grade =89

change in grade=(first exam grade)-(second exam grade)

change in grade=94-89

change in grade=5

Percentage = ( change in grade)/( first exam grade) *100

so, percentage is

=\frac{5}{94}\times 100

so,

the percent of change in Max's grade to the nearest whole percentage was 5%..........Answer



Akimi4 [234]3 years ago
5 0

Answer:

<em>The percent of change in grade was "5% decrease"</em>

Step-by-step explanation:

Max's grade on the first math exam was 94 and his grade on his second math exam was 89.

So, the <u>grade is decreased by</u> (94 - 89) = 5

For finding the percentage of change in grade, we will just <u>divide the "grade decreased" by the "initial grade" and then multiply that by 100%</u>.

So,  \frac{5}{94}\times 100\% = \frac{500}{94}\%= 5.31...\% \approx 5\%

Thus, the percent of change in Max's grade to the nearest whole percent was  5% decrease.

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The sum of two numbers is 82. The difference of the two numbers is 62. What are the two numbers?
Alja [10]

Answer

22

Step-by-step explanation:

82-2=80-60=20+2=22

4 0
3 years ago
Help me ASAP please!!!
tia_tia [17]

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6 0
3 years ago
Andrew is showing his work in simplifying (−5.7 + 2.2) − 1.1.
Leviafan [203]
Answer: In step 1, Andrew used the commutative property

Explanation:
In step 1 he used commutative, which is a + b = b + a
(- 5.7 + 2.2) = 2.2 + (- 5.7)

Step 2, he used associative property, not the distributive.

Step 3, he just added5.7 + 1.1 = 6.8

Step 4, he distributed the negative sign:
- (6.8) = - 6.8
6 0
3 years ago
Read 2 more answers
Find the sum of integers from 33 to 47:
ICE Princess25 [194]

Answer:

Step-by-step explanation:There are formulas to work this out, but you can also suss out an answer by a liberal application of critical thinking.

Okay, you want to add 51 + 52 + 53 + … + 99 + 100, right? (The … represents all the numbers in between, in case you were wondering.)

Well, that’s a total of 50 numbers. And if you know anything about addition, you know that it doesn’t matter what order you add them.

So you could also say 51 + 100 + 52 + 99 + 53 + 98 + … and so on.

Let’s see what happens. 51 + 100 = 151. So far so good.

Then, 52 + 99 also equals 151. And 53 + 98 also equals 151. Since there are 50 numbers, that’s 25 pairs that are going to add up to 151.

151 + 151 + 151 + 151 + … (21 more instances of 151).

So we can simplify our workload a bit. Instead of adding up all the numbers by hand, we can just multiply 151 by 25.

151 x 25 = 3775

From that, we can work out a generic formula that will allow you to add any sequence of numbers…without actually adding.

Let a be the first number in the sequence, and let n be the last number in the sequence. The number of numbers is (n - a) + 1. (You have to add 1, because if you just subtract, it’s like you’re losing the lowest number in the sequence).

So…you get the sum by adding the first and last number in the sequence, and then multiplying that result by half of the total number of numbers.

(a+n)((n−a)+12)  

an−a2+a+n2−an+n2  

−a2+a+n2+n2  

−a(a−1)+n(n+1)2  

Let’s check to see if it works!

−51(51–1)+100(100+1)2  

−51(50)+100(101)2  

−2550+10,1002  

75502  

3775  

Note that if the starting number were 1, the formula would simplify to  n(n+1)2

8 0
3 years ago
Read 2 more answers
What are the zeros of the quadratic function f(x) = 6x2 – 24x + 1?<br><br> fast please
xxTIMURxx [149]

Answer:      6(x²-4x+4-4)+1=0, 6(x-2)²-24+1=0, 6(x-2)²=23, x-2=±√(23/6), x=2±√(23/6)=2±1.95789, so x=3.95789 or 0.04211 approx. these are the zeros.

step by step explanation:

\boxed{\boxed{\dfrac{12+\sqrt{138}}{6},\ \dfrac{12-\sqrt{138}}{6}}}

Solution-

The quadratic function is,

6x^2-24x + 1

a = 6, b = -24, c = 1

x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}

=\dfrac{-(-24)\pm \sqrt{-24^2-4\cdot 6\cdot 1}}{2\cdot 6}

=\dfrac{24\pm \sqrt{576-24}}{12}

=\dfrac{24\pm \sqrt{552}}{12}

=\dfrac{24\pm 2\sqrt{138}}{12}

=\dfrac{12\pm \sqrt{138}}{6}

=\dfrac{12+\sqrt{138}}{6},\ \dfrac{12-\sqrt{138}}{6}

4 0
3 years ago
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