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kobusy [5.1K]
3 years ago
7

Write the addition or subtraction shown by the number line

Mathematics
2 answers:
erastova [34]3 years ago
5 0
4 is the correct answer
Zigmanuir [339]3 years ago
4 0
-3+7=4 should be your answer
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Angle BAC measures 56°.
wel

Answer:

56

Step-by-step explanation:

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Haily paid $13 for 1 and 3/7 kf of sliced salami. What was the cost per kilogram of salami?
nikdorinn [45]

13 divided by 1 and 3/7=9 and 1/10

$9.10

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Find the general solution for the differential equation (dy)/(dx) + 3y = 18<br> Y=
harkovskaia [24]

Answer:

y=-e^{-3x-c_1}+6

Step-by-step explanation:

\frac{dy}{dx}+3y=18\\\\\mathrm{Substitute\quad }\frac{dy}{dx}\mathrm{\:with\:}y'\:\\\\y'\:+3y=18\\\\Rewrite\\\\\frac{1}{6-y}y'\:=3\\\\Solve \::\frac{1}{6-y}y'\:=3\\\\-In(6-y)=3x+c_1\\\\Isolate\:y\\\\\\y=-e^{-3x-c_1}+6

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3 years ago
The Hudson Bay tides vary between 3 feet and 9 feet. The tide is at its lowest point when time (t) is 0 and completes a full cyc
BaLLatris [955]

Answer:

y(t)= 6-3cos(\dfrac{2\pi}{14}t )

Step-by-step explanation:

The function that could model this periodic phenomenon will be of the form

y(t) = y_0+Acos(wt)

The tide varies between 3ft and 9ft, which means its amplitude A is

A =\dfrac{(9-3)ft}{2} \\\\\boxed{A = 3ft}

and its midline y_0 is

y_o=3+3 \\\\\boxed{y_o= 6ft}.

Furthermore, since at t=0 the tide is at its lowest ( 3 feet ), we know that the trigonometric function we must use is -cos(\omega t).

The period of the full cycle is 14 hours, which means

\omega t =2\pi

\omega (t+14)= 4\pi

giving us

\boxed{\omega = \dfrac{2\pi}{14}.}

With all of the values of the variables in place, the function modeling the situation now becomes

\boxed{y(t)= 6-3cos(\dfrac{2\pi}{14}t ).}

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3 years ago
If Asher plays each of the remaining seasons for which he is eligible, what is the average number of doubles he needs to hit per
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Answer:

the

Step-by-step explanation:

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3 years ago
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