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Orlov [11]
3 years ago
6

1/5 + 5/13 - 3/14 = ?

Mathematics
1 answer:
forsale [732]3 years ago
3 0

Answer:

\frac{337}{910}

Step-by-step explanation:

\frac{1}{5}+\frac{5}{13}-\frac{3}{14}

Lowest Common Multiple of 5, 13 and 14 = 910

Convert the fractions based on the denominator:

\frac{182}{910}+\frac{350}{910}-\frac{195}{910}

Combine the fractions since the denominator is the same:

\frac{182+350-195}{910}

\frac{337}{910}

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H(x) = x^2 + 1 k(x) = x – 2<br> (h + k)(2)=?
likoan [24]
First we will compute the h+k and then multiply the result by 2.
To add polynomials, we add terms whose variables are alike, for example:
we add the coefficients of x^2 together, the coefficients of x together and so on.

Therefore:
h + k = x^2 + 1 + x - 2 = x^2+x-1

Now, we will multiply this answer by 2 to get the final answer:
2(h+k) = 2(x^2+x-1) = 2x^2 + 2x -2
6 0
3 years ago
A. 792 432,795<br> What is 432,795 divided by 792
Fittoniya [83]
It is 546.4583333333333, which would simplify to 546.46 if to the hundredths place or 546.5 to the tens place
8 0
3 years ago
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Can you help me round 3,418,913 to the nearest thousand
Kamila [148]
3,419,000 because the 913 rounds the number up
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Plss help me TT
Marina CMI [18]

a. There are 0 or 2 real positive roots for the equation and

b. There are 0 or 2 real negative roots for the equation.

<h3>What is the Descartes'rule of sign?</h3>

Descartes' rule of sign states that

  • The number of real positive zero of a polynomial f(x) is the number of sign changes of the coefficients of f(x) or an even number less than the number of sign changes of the coefficients of f(x)
  • The number of real negative zero of a polynomial f(x) is the number of sign changes of the coefficients of f(-x) or an even number less than the number of sign changes of the coefficients of f(-x)

<h3>How to find the number of possible positive and negative roots are there for the equation?</h3>

Given the equation 0 = −8x¹⁰ − 2x⁷ + 8x⁴ − 4x² − 1, writing it as a polynomial function, we have f(x) = −8x¹⁰ − 2x⁷ + 8x⁴ − 4x² − 1

<h3>a. The number of positive roots</h3>

So, to find the number of positive roots, we find the number of sign changes of the polynomial f(x).

So, f(x) = −8x¹⁰ − 2x⁷ + 8x⁴ − 4x² − 1

Since f(x) has coefficients -8, -2, + 8, -4, -1, there are two sign changes from -2 to + 8 and from + 8 to -4.

So, there are 2 or 2 - 2 = 0 real positive roots.

So, there are 0 or 2 real positive roots for the equation.

<h3>b. The number of negative roots</h3>

So, to find the number of negative roots, we find the number of sign changes of the polynomial f(-x).

So, f(-x) = −8(-x)¹⁰ − 2(-x)⁷ + 8(-x)⁴ − 4(-x)² − 1

= −8x¹⁰ + 2x⁷ + 8x⁴ − 4x² − 1

Since f(x) has coefficients -8, +2, + 8, -4, -1, there are two sign changes from -8 to + 2 and from + 8 to -4.

So, there are 2 or 2 - 2 = 0 real negative roots.

So, there are 0 or 2 real negative roots for the equation.

So,

  • There are 0 or 2 real positive roots for the equation and
  • There are 0 or 2 real negative roots for the equation.

Learn more about Descartes' rule of sign here:

brainly.com/question/28487633

#SPJ1

8 0
1 year ago
PLZ HURRY !!!!! Different shapes are drawn on cards and then the cards are placed in a bag. The number of cards for each shape i
bazaltina [42]
70%
12+27+91 = 130
91/130 = .7
.7x100 = 70%
___
.700
7.00
70.0

Answer is 70%
5 0
3 years ago
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