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Arisa [49]
3 years ago
10

Which of the following is the function represented by the graph?

Mathematics
2 answers:
Simora [160]3 years ago
8 0

Answer:

It’s D y=1/(x-5) +3

Step-by-step explanation:

I just did it

frozen [14]3 years ago
4 0

Answer:

its d

Step-by-step explanation:

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Answer:

(a) is 8 x 7 x 3 = 168

(b) is 8 x 7 = 56

(b2) is weird I don't know what it's asking

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2 years ago
What is the equation, in point-slope form, of the line that is perpendicular to the given line and passes through the
Svetradugi [14.3K]

keeping in mind that perpendicular lines have negative reciprocal slopes, hmmmm what's the slope of that line above anyway,

\bf (\stackrel{x_1}{1}~,~\stackrel{y_1}{-1})\qquad (\stackrel{x_2}{4}~,~\stackrel{y_2}{2}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{2}-\stackrel{y1}{(-1)}}}{\underset{run} {\underset{x_2}{4}-\underset{x_1}{1}}}\implies \cfrac{2+1}{3}\implies 1 \\\\[-0.35em] ~\dotfill

\bf \stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}} {\stackrel{slope}{\underline{1}\implies \cfrac{\underline{1}}{1}}\qquad \qquad \qquad \stackrel{reciprocal}{\cfrac{1}{\underline{1}}}\qquad \stackrel{negative~reciprocal}{-\cfrac{1}{\underline{1}}\implies -1}}

so we're really looking for the equation of a line whose slope is -1 and runs through (2,5)

\bf (\stackrel{x_1}{2}~,~\stackrel{y_1}{5})~\hspace{10em} \stackrel{slope}{m}\implies -1 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{5}=\stackrel{m}{-1}(x-\stackrel{x_1}{2}) \\\\\\ y-5=-x+2\implies y=-x+7

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2 years ago
Read 2 more answers
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Without that value, we can't solve your problem, unless you are looking for an algebraic equation.

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I hope this is correct.

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It has to do with the number of dimensions you have in the figure. For example, in a square you have 2 dimensions, length and width. Since you have only two you use units^2. In a cube, you have 3 dimensions, length, width and height, which is where you get the units^3. 
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