Question

6.03

Answer 1

Both answers are C for #4 and #5

Answer 2

Answer:

Ques 4)

The system is:

                      $y=x-4$

                     $y=\dfrac{x-4}{x+2}$

Ques 5)

The system is:

                         $6x+y=-27$

             and     $y=x^2+5x+3$  

Step-by-step explanation:

Ques 4)

After looking at the graph we observe that :

The first graph is a line which passes through (4,0) and (0,-4)

Hence, the equation of such a line is:

                y=x-4

and the second graph is a curve such that the vertical asymptote is at x= -2

and also x= 4 is a root of the rational function.

Since, the graph passes through (4,0)

Hence, the system equation which best represents the graph is:

                           $y=x-4$

                     $y=\dfrac{x-4}{x+2}$

Ques 5)

One of the curve is :

a line that passes through (-5,3) and (-6,9)

Hence, the equation of line is given by:

$y-3=\dfrac{9-3}{-6-(-5)}\times (x-(-5))\\\\i.e.\\\\y-3=\dfrac{6}{-6+5}\times (x+5)\\\\i.e.\\\\y-3=\dfrac{6}{-1}\times (x+5)\\\\i.e.\\\\y-3=-6(x+5)\\\\i.e.\\\\y-3=-6x-30\\\\i.e.\\\\y=-6x-30+3\\\\i.e.\\\\y=-6x-27$

i.e. Equation of line is:

$6x+y=-27$

While the other graph is a upward facing parabola such that the vertex is in third quadrant this means that the coefficient of x^2 must be positive and that of x must also be positive.

Hence, the system in which the equation of line satisfies is:

                          $6x+y=-27$

             and     $y=x^2+5x+3$