All categories

4 years ago

If I subtract the square of one integer from the square of another, the difference could be

Mathematics

1 answer:

SIZIF [17.4K]4 years ago

3 0

Answer:

The answer is C

Step-by-step explanation:

You might be interested in

For place values that occur to the left of the decimal point, each place value is ten times ______ than the place value to its r

Llana [10]

D. think about it this way. the closer it is to decimal, the closer it is to a whole number which is the "biggest"

8 0

3 years ago

I LOVE SINJIN VAN CLEEF<33

Montano1993 [528]

lol what is that. delete it

5 0

3 years ago

Read 2 more answers

The sum of the first 12 terms of a geometric sequence with 10 as the first term and a common ratio of 0.3 is __________.

BaLLatris [955]

Answer: 14.2638366937

Step-by-step explanation:

A geometric sequence is a sequence in which each term is multiplied by a number, called the common ratio, to get the next term.

So, if the first term of the geometric sequence is 10 and the common ratio is 0.3, the sequence would be 10, 0.3(10), 0.3 x 0.3 x 10... and so forth. This becomes:

10, 3, 0.9, 0.27, 0.081, 0.00243, 0.00729, 0.002187, 0.0006561, 0.00019683, 0.000059049, 0.0000177147...

You add these first 12 terms to get 14.2638366937.

7 0

3 years ago

g A researcher wants to construct a 95% confidence interval for the proportion of children aged 8-10 living in Atlanta who own a

Helga [31]

Answer:

The sample size needed is 2401.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The margin of error of the interval is:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

Estimate the sample size needed if no estimate of p is available so that the confidence interval will have a margin of error of 0.02.

We have to find n, for which M = 0.02.

There is no estimate of p available, so we use $\pi = 0.5$

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.02 = 1.96\sqrt{\frac{0.5*0.5}{n}}$

$0.02\sqrt{n} = 1.96*0.5$

$\sqrt{n} = \frac{1.96*0.5}{0.02}$

$(\sqrt{n})^{2} = (\frac{1.96*0.5}{0.02})^{2}$

$n = 2401$

The sample size needed is 2401.

7 0

3 years ago

Read 2 more answers

There are nine balls. One is slightly lighter than the rest; the difference is small enough that you can't tell just by picking

icang [17]

<span>You will need to weight those balls only twice. You weight 6 balls, 3 on one side of weight and 3 on another, and other 3 balls you have are in your hand.

Check picture bellow</span>

8 0

3 years ago

Read 2 more answers