Took 3 of us in grade 10 but johns present age is 77.5 and his sister is 72.5
Answer:
μ = 5.068 oz
Step-by-step explanation:
Normal distribution formula to use the table attached
Z = (x - μ)/σ
where μ is mean, σ is standard deviation, Z is on x-axis and x is a desired point.
98% of 6-oz. cups will not overflow means that the area below the curve is equal to 0.49; note that the curve is symmetrical respect zero, so, 98% of the cases relied between the interval (μ - some value) and (μ + some value)].
From table attached, area = 0.49 when Z = 2.33. From data, σ = 0.4 oz and x = 6 oz (maximum capacity of the cup). Isolating x from the formula gives
Z = (x - μ)/σ
2.33 = (6 - μ)/0.4
μ = 6 - 2.33*0.4
μ = 5.068
This means that with a mean of 5 oz and a standard deviation of 0.4 oz, the machine will discharge a maximum of 6 oz in the 98% of the cases.
Answer: c
-1.9+16= 14.1
14.1-7.1= 7.0
Answer:
8 sand bags can be carried along.
Step-by-step explanation:
First you want to subtract 300-140. That subtracts the pilots weight giving you the maximum weight capacity left. (160) Then you want to divide 160 (the weight that can be carried) by 20 (the weight of the sand bags) after doing that you will get 8. And that is how i got 8 sand bags as my answer.
The normal body temperature : to = 37° C
An inequality is:
| t - to | ≤ 3
| t - 37 | ≤ 3
t - 37 ≤ 3 AND ( - t - 37 ) ≤ 3
t ≤ 3 + 37 - t + 37 ≤ 3
t ≤ 40 - t ≤ 3 - 37
- t ≤ - 34 / * ( - 1 )
t ≥ 34
Answer t ∈ [ 34°C, 40° C ].